All categories

3 years ago

Read the scenario. A horse accelerates +2 mi/h/s south. Which option defines the horse’s acceleration?

Physics

1 answer:

Yanka [14]3 years ago

3 0

Answer:

D) The horse’s velocity increases by 2 mi/h every 1 s as the horse moves south

Explanation:

Let's analyze all options:

A. The horse’s speed changes to 2 mi/h as the horse moves south The horse's speed is not 2 mi/h, but it increases 2 mi/h every second. So, this is false.

B. The horse’s speed decreases by 2 mi/h every 1 s. It would only decrease if the horse was moving north. Otherwise this is false.

C. The horse’s position decreases by 2 mi every 1 s as the horse moves south. It is not horse's position but its velocity what changes 2mi/h every second. Also false.

D. The horse’s velocity increases by 2 mi/h every 1 s as the horse moves south. Since given acceleration is positive, you can say that its velocity increases 2mi/h every second. So, this is true

You might be interested in

A can of beans that has mass M is launched by a spring-powered device from level ground. The can is launched at an angle of α0 a

scZoUnD [109]

Hi there!

Since the can was launched from ground level, we know that its trajectory forms a symmetrical, parabolic shape. In other words, the time taken for the can to reach the top is the same as the time it takes to fall down.

Thus, the time to its highest point:
$T_h = \frac{T}{2}$

Now, we can determine the velocity at which the can was launched at using the following equation:
$v_f = v_i + at$

In this instance, we are going to look at the VERTICAL component of the velocity, since at the top of the trajectory, the vertical velocity = 0 m/s.

Therefore:
$0 = v_y + at\\\\0 = vsin\theta - g\frac{T}{2}$

***vsinθ is the vertical component of the velocity.

Solve for 'v':
$vsin(\alpha_0) = g\frac{T}{2}\\\\v = \frac{gT}{2sin(\alpha_0)}$

Now, recall that:
$W = \Delta KE = \frac{1}{2}m(\Delta v)^2$

Plug in the expression for velocity:
$W = \frac{1}{2}M (\frac{gT}{2sin(\alpha_0)})^2\\\\\boxed{W = \frac{Mg^2T^2}{8sin^2(\alpha _0)}}$

We can use the same process as above, where T' = 2T and Th = T.

$v = \frac{gT}{sin(\alpha _0)} }\\\\W = \frac{1}{2}M(\frac{gT}{sin(\alpha _0)})^2\\\\\boxed{W = \frac{Mg^2T^2}{2sin^2(\alpha _0)}}$

The work done in part B is 4 times greater than the work done in part A.

$\boxed{\frac{W_B}{W_A} = \frac{4}{1} = 4.0}$

4 0

2 years ago

What kind of waves can cause the most damage on the earth's surface?

Karo-lina-s [1.5K]

Answer:

Surface waves, in contrast to body waves can only move along the surface. They arrive after the main P and S waves and are confined to the outer layers of the Earth. They cause the most surface destruction. Earthquake surface waves are divided into two different categories: Love and Rayleigh.

Explanation:

Hope this helped Mark BRAINLIEST!!!

4 0

3 years ago

Read 2 more answers

How do we use information from earths climate change data in order to engineer soulutions that reduce carbon emissions and impac

masya89 [10]

Answer:

That is a very broad question. One thing that does not seem to be considered is the depletion of the ozone layer at high altitudes.

In the 1960's chlorofluorcarbons (CFC,s) became popular as refrigerants, spray can propellants, etc. In January 1989 the Montreal Protocol was passed which has greatly reduced the use of these substances. However, it may be several decades before the ozone layer can be replaced and again absorb harmful ulraviolet rays that may be partly responsible for the increase in global warming.

(One chlorine atom at high altitudes can be responsible for the destruction of 100,000 molecules of ozone - catalytic reaction)

7 0

2 years ago

A track is traveling a. a speed of 25.0 m/s along a level road. A crate is resting on the bed of the truck, and the coefficient

Mice21 [21]

To solve this problem it is necessary to apply the concepts related to

conservation of energy, for this case manifested through work and kinetic energy.

$W = \Delta KE$