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murzikaleks [220]
4 years ago
9

Which of the following microscope parts should routinely be adjusted to control the light source and provide optimal illuminatio

n of the specimen?
Physics
1 answer:
yKpoI14uk [10]4 years ago
3 0
Here is the answer. The microscope parts that should routinely be adjusted to control the light source and provide optimal illumination of the specimen are the following: <span>light source; condenser; specimen; objective lens; ocular lens. Hope this answers your question.</span>
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how long would it take a 3.4 kg bike with 79 kg rider traveling at 18.6 m/s to stop if 867 N of force is applied to the brakes?
nalin [4]

Answer: 1.76 s

Explanation:

We have the following data:

m=3.4 kg+79 kg=82.4 kg is the total mass of the bike and the rider

V_{o}=18.6 m/s is the initial velocity

F=867 N is the force applied to the brakes

Firstly, we will find the acceleration a with the following equation:

F=m.a (1)

Isolating a:

a=\frac{F}{m} (2)

a=\frac{867 N}{82.4 kg} (3)

a=10.52 m/s^{2} (4) This is the magnitude of the acceleration, however, since the final velocity is 0 m/s, this means the direction is negative

Hence:

a=-10.52 m/s^{2} (5)

On the other hand, with the following equation we can find the time t:

V=V_{o}+at (6)

Where:

V=0 m/s is the final velocity (the bike stops)

Isolating t:

t=-\frac{V_{o}}{a} (7)

t=-\frac{18.6 m/s}{-10.52 m/s^{2}} (8)

Finally:

t=1.76 s This iste time it takes to the bike to stop

7 0
3 years ago
Which statement demonstrates that ultraviolet (UV) rays are electromagnetic waves?
MA_775_DIABLO [31]
The answer is B) They do NOT require a medium to travel.
5 0
3 years ago
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What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

#SPJ4

6 0
2 years ago
Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo
MrRa [10]

Explanation :

Takumi wears sunscreen and a hat each time he works in the yard. This is to protect himself with the strong radiation coming from the sun. UV rays that are coming from the sun are the main cause of skin cancer.

Stochastic effects are the effects that are caused by chance. Cancer is one of the main stochastic effects.

So, the correct option is (b) "the severity of stochastic effects, such as cancer".

7 0
4 years ago
Read 2 more answers
A satellite that weighs 4900 N on the launchpad travels around the earth's equator in a circular orbit with a period of 1.667 h.
charle [14.2K]

Answer:

(a)F= 3.83 * 10^3 N

(b)Altitude=8.20 * 10^5 m

Explanation:

On the launchpad weight = gravitational force between earth and satellite.

W = GMm/R²

where R is the earth radius.

Re-arranging:

WR² / GM = m

m = 4900 * (6.3 * 10^6)² / (6.67 * 10^-11 * 5.97 * 10^24) = 488 kg

The centripetal force (Fc) needed to keep the satellite moving in a circular orbit of radius (r) is:

Fc = mω²r

where ω is the angular velocity in radians/second. The satellite completes 1 revolution, which is 2π radians, in 1.667 hours.

ω = 2π / (1.667 * 60 * 60) = 1.05 * 10^-3 rad/s

When the satellite is in orbit at a distance (r) from the CENTRE of the earth, Fc is provided by the gravitational force  between the earth and the satellite:

Fc = GMm/r²

mω²r = GMm / r²

ω²r = GM / r²

r³ = GM/ω² = (6.67 * 10^-11 * 5.97 * 10^24) / (1.05 * 10^-3)²  

r³ = 3.612 * 10^20

r = 7.12 * 10^6 m

(a) F = GMm/r²  

F=(6.67 * 10^-11 * 5.97 * 10^24 * 488) / (7.12 * 10^6 )²

F= 3.83 * 10^3 N

(b) Altitude = r - R = (7.12 * 10^6) - (6.3 * 10^6) = 8.20 * 10^5 m

4 0
3 years ago
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