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3 years ago

A cathedral hull allows a boat to do what?

Physics

1 answer:

nirvana33 [79]3 years ago

7 0

Answer: A cathedral hull allows a boat to

(Get up on a plane quicker)

Explanation:

A boat is a device that is used for water transportation and other purposes. It is made up of various parts which includes:

- The HULL: this is the base( bottom) of a boat with the pointy forward part called the BOW and the flat back part called the STERN.

There are different types of hulls which can be constructed by boat manufacturers and it depends on the use of the boat. They include:

1.)displacement hull,

2.)planing hull,

3.) flat hull,

4.) round hull,

5.)v-shaped hull and

6.) multi-hulled boats.

Cathedral hull is a planing hull that allows a boat to get on a plane quicker. A boat is said to be "on a plane" when more power (and speed) is applied, lift increases, and the boat, in effect, rides over its bow wave, reducing wetted area and thus reducing drag. I hope this helps, thanks.

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2. A multipurpose wiring tool can be used to

Alex_Xolod [135]

Answer:

Option C

Crimp terminals

Explanation:

It's possible to crimp terminals using a multipurpose wiring tool. Since the tool selected for use during crimping also depends on the volume of work, the multipurpose wiring tool is recommended for use when the volume is small to medium. Basically, crimping tools are sized according to the wire gauge that they can fit. Since multipurpose has different sizes, that's why it's used for crimping tools.

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4 years ago

Suppose you pour 0.250 kg of 20.0°C water into a 0.600 kg aluminum pan off the stove with a temperature of 173°C. Assume that th

lapo4ka [179]

Answer:

$T_f=5.0116^{\circ}C$

Explanation:

Given:

mass of water, $m_w=0.25\ kg$

initial temperature of water, $T_i_w=20^{\circ}C$

initial temperature of pan, $T_i_p=173^{\circ}C$

mass of pan, $m_p=0.6\ kg$

mass of water evapourated, $m_v=0.03\ kg$

specific heat of water, $c_w=4186\ J.kg^{-1}.K^{-1}$

specific heat of aluminium pan, $c_a=900\ J.kg^{-1}.K^{-1}$

latent heat of vapourization, $L=2256000\ J.kg^{-1}$

Using the equation of heat:

Here, initially certain mass of water is vapourised first and then the remaining mass of water comes in thermal equilibrium with the pan.

$m_p.c_a.(T_{ip}-T_f)=m_v.L+(m_w-m_v).c_w.(T_f-T_{iw})$

$0.6\times 900\times (173-T_f)=0.03\times 2256000+(0.25-0.03)\times 4186\times (T_f-20)$

$T_f=5.0116^{\circ}C$

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3 years ago

Suppose a rocket is traveling through space and moving at a speed close to the speed of light. Three minutes pass on the rocket

Sedbober [7]

Answer:

Explanation:

on edge2020

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3 years ago

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Keisha finds instructions for a demonstration on gas laws. 1. Place a small marshmallow in a large plastic syringe. 2. Cap the s

lana [24]

The correct answer is option C. This is a demonstration of Boyle’s law. As the volume increases, the pressure decreases, and the marshmallow will grow larger.

Keisha follows the instructions for a demonstration on gas laws.
1. Place a small marshmallow in a large plastic syringe.
2. Cap the syringe tightly.
3. Pull the plunger back to double the volume of gas in the syringe.

Now, this activity is being done at the same temperature, because there is no mention of the temperature change. Thus, when the plunger is pulled back, the volume doubles, so pressure will decrease. Therefore, This is a demonstration of Boyle’s law. As the volume increases, the pressure decreases, and the marshmallow will grow larger.

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4 years ago

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Zepler [3.9K]

Answer:

It is d. 0.80
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3 years ago