The equations 4 x minus 5 y = 5, 3 x + 10 y = 20, 4 x minus 5 y = negative 5, and 3 x + 10 y = negative 20 are shown on the grap
h below. On a coordinate plane, there are 4 lines. Green line goes through (0, 1) and (2.5, 3). Orange line goes through (0, negative 1) and (2.5, 1). Blue line goes through (0, 2) and (3.5, 1). Pink line goes through (0, negative 2) and (3.5, negative 3). Which system of equations has a solution of approximately (–2.7, –1.2)? 4 x minus 5 y = negative 5 and 3 x + 10 y = negative 20 4 x minus 5 y = 5 and 3 x + 10 y = 20 4 x minus 5 y = 5 and 3 x + 10 y = negative 20 4 x minus 5 y = negative 5 and 3 x + 10 y = 20
2 answers:
Answer:
4 x minus 5 y = negative 5 and 3 x + 10 y = negative 20
Step-by-step explanation:
The equations
4 x - 5 y = 5 (red)
3 x + 10 y = 20 (blue)
4 x - 5 y = -5 (green)
3 x + 10 y = -20 (purple)
are shown in the picture attached. As we can see there, the point (–2.7, –1.2) is on the intersection of the purple and green lines. Therefore is the solution of the system:
4 x - 5 y = -5
3 x + 10 y = -20
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