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spayn [35]
3 years ago
14

A rocket is launched at an angle of 56.0 degrees above the horizontal with an initial speed of 105 m/s. The rocket moves for 3.0

0 s along its initial line of motion with an acceleration of 28.0 m/s^2. At the time, it’s engines fail and the rocket proceeds to move as a projectile
Physics
1 answer:
Nataly [62]3 years ago
4 0
V = u + at 
<span>= 100 + 30*3 = 190 m/s </span>

<span>lets call the maximum altitude of the rocket H and say that the height reached while the engines are running is h. Also we'll call the angle of the launch a. </span>

<span>we can get an expression for h as follows. </span>

<span>h = vsin(a)t + (1/2)at^2 </span>
<span>h = 100*sin(53)*3 + 0.5*30*9 </span>
<span>h = 374.6 m </span>

<span>and we can write an expression for the time it takes the rocket to reach maximum height after the engines have failed. </span>

<span>t = [0 - vsin(a)]/-g </span>
<span>= vsin(a)/g </span>

<span>then </span>

<span>H-h = vsin(a)t - 1/2*gt^2 </span>

<span>if we sub in the expression for t and rearrange we get </span>

<span>H-h = [(vsin(a)^2]/2g </span>

<span>now add h </span>

<span>H = [(vsin(a)^2]/2g + h </span>

<span>H = 1549 m </span>

<span>b) </span>

<span>to obtain the total time of flight, first work out the time it takes for the rocket to fall from the top of its trajectory. </span>

<span>t = (v-u)/g </span>

<span>where v is now the final vertical velocity and u is the initial vertical velocity. </span>

<span>to get v </span>

<span>v^2 = u^2 + 2gH </span>

<span>so t = [Sqrt(2gH)]/g </span>

<span>now the total time is the falling time plus the time the engines are running, plus the time we calculated previously. </span>

<span>t = [Sqrt(2gH)]/g + 3 + vsin(a)/g </span>
<span>t = 36.72 s </span>

<span>c) </span>

<span>calculating the range is simple since the horizontal velocity stays the same for most of the flight. </span>

<span>We just need to work out the bit of distance traveled while the rocket accelerates for the first 3 seconds of flight. </span>

<span>r = ut + 1/2at^2 </span>
<span>r = 100*3+0.5*30*9 </span>
<span>r = 435 m </span>

<span>now we take the remaining flight time and put it in the following formula to work out the rest of the distance. </span>

<span>R-r = vcos(a)t </span>

<span>= 190*cos(53)*33.72 </span>
<span>= 3856 m </span>

<span>add this to the previous distance we calculated to obtain the range </span>

<span>R = 3856 + 435 </span>
<span>R = 4291 m </span>

<span>Hopefully that's right, I may have made an error in there so make sure you check through these calculations yourself to confirm. Hope this helps. :)</span>
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siniylev [52]

Answer:

Option 3. The tennis ball began from rest and rolls at a rate of 14.7 m/s safer 1.5 seconds.

Explanation:

To know the the correct answer to the question, it is important that we know the definition of acceleration.

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) /t

Where

a => acceleration

v => final velocity

u => Initial velocity

t => time

With the above information in mind, let us consider the options given in the question above to know which conform to the difinition of acceleration.

For Option 1,

We were told that the tennis ball has the following:

Distance = 4 m

Time = 1.5 s

This talks about the speed and not the acceleration.

Speed = distance / time

For Option 2,

We were only told about the average speed and nothing else.

For Option 3,

We were told that the tennis ball have the following:

Initial velocity (u) = 0 m/s

Final velocity (v) = 14.7 m/s

Time = 1.5 s

This talks about the acceleration.

a = (v – u) /t

For Option 4,

We were only told that the tennis rolls to the right at an average speed. This talks about the average velocity. We need more information like time to justify the acceleration.

From the above illustrations, option 3 gives the correct answer to the question.

8 0
3 years ago
Which of the following is most closely related to the specific heat of a substance?A. its temperatureB. its melting pointC. its
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Answer:

option (C)

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Its SI unit is Joule / Kg °C.

Every material has a constant value of specific heat.

So, option (c) is correct.

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3 years ago
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EastWind [94]

Answer:

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Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 are the masses of the object and Earth itself. and R distance between, or the Earth radius.

So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}

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\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2

Since M_2 = 2m_2 and r = R/3

\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5

So gravity would have been decreased by a factor of 4.5  

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