1: 66/100
2: 1 8/100
3: 1 21/100
4: 52/100
5: 1 71/100
6: 97/100
Try this solution:
1. for probability of both televisions work:

2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):
- for P(1defective);
- for P(2defective);
totaly for at least one is defective:

Answer:
(3, -1)
Step-by-step explanation:
Answer:
(write them out and convert them all into mixed fractions)
(find the LCD aka least common denominator)
(add all numerators together)
(this is improper, so you need to convert back to mixed by dividing)
(this is your answer)