Question

Kevin sold a box of 28 books at a yard sale for a total of $54.64. He sold the paperback books for $1.68 each and sold the hardcover books for $2.44 each. Which system of equations can be used to determine the number of $1.68 paperback books, x, and the number of $2.44 hardcover books, y, that were sold at the yard sale?
A.
x + y = 28
1.68x + 2.44y = 54.64

B.
2.44x - 1.68y = 28
x + y = 54.64

C.
x + y = 28
2.44y = -1.68x + 54.64

D.
y = x - 54.64
1.68x + 2.44y = 28

Answer 1

Answer:

A.  

x + y = 28

1.68x + 2.44y = 54.64

Step-by-step explanation:

Let x = paperback books and y = hardback books

x+y =28

We know that paperbacks cost 1.68 and hardback cost 2.44

1.68x + 2.44y = 54.64

We have 2 equations and 2 unknowns

x+y =28

1.68x + 2.44y = 54.64