Answer:
The displacement of Sudhir is 0.781 km.
Explanation:
Given;
initial distance, d₁ = 0.4 km = 400 m, N60.0°W
final distance, d₂ = 0.5 km
Make a sketch of Sudhir motion to form a right angled triangle;
(Check image uploaded).
Apply cosine rule to determine d "displacement"
d² = 500² + 400² - (2 x 500 x 400 x cos 120)
d² = 410,000 - (400,000 x -0.5)
d² = 410,000 - (-200,000)
d² = 410,000 + 200,000
d² = 610,000
d = √610000
d = 781.03 m
d = 0.781 km
Therefore, the displacement of Sudhir is 0.781 km.
No it isn't because acceleration is the <span>increase in the rate or speed of something.</span> It's going at a constant rate.
the answer is correct why.
EXPLANATION:
First copy the 15 and u will × now in the no. of (9.8 ×1.5) the equal is 15 m/s -14.7m/s so we - the now the 15-14.7 and the ANSWER IS 0.3m/s.
Explanation:
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<em>D</em><em>O</em><em>N</em><em>T</em><em> </em><em>F</em><em>O</em><em>R</em><em>G</em><em>E</em><em>T</em><em> </em><em>M</em><em>A</em><em>'</em><em>R</em><em>K</em><em> </em><em>M</em><em>E</em><em> </em><em>A</em><em>S</em><em> </em><em>A</em><em> </em><em>B</em><em>R</em><em>I</em><em>N</em><em>L</em><em>I</em><em>S</em><em>T</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>F</em><em>O</em><em>L</em><em>L</em><em>O</em><em>W</em><em> </em><em>M</em><em>E</em>
At night, when that part of Earth is facing away from the Sun<span>, </span>space<span> looks </span>black<span>because there is no nearby bright source of light, like the </span>Sun<span>, to be scattered. </span>If<span> you were on the Moon, which has no atmosphere, the sky would be </span>black<span> both night and day.</span>
<h2>Answer:</h2>
<u>It is deflecting towards point X because it is hitting the proton or neutron</u>
<h2>Explanation:</h2>
The experiment shows the model of Rutherford atomic model and he concluded that every atom contains a nucleus where all of its positive charge and most of its mass are concentrated. So when the ray passes straight it meant that most of the place inside atom is empty but when it directly hits the neucleus it would come back at 180 degrees and when it passes with neucleus it bends away with the angle of 90 degrees.