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3 years ago

A family took a trip in a car traveling East from Greensboro to Wilmington, NC. Use the Graph to answer the questions below.

Physics

1 answer:

kotykmax [81]3 years ago

7 0

Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

Therefore, average speed of the trip = $\frac{\text{Total distance covered}}{\text{Total time taken}}$

From the graph attached,

Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

= 90 meters

Total time taken = 60 seconds

Average speed = $\frac{90}{60}$

= 1.5 meter per second

2). Velocity is a vector quantity.

Therefore, average velocity = $\frac{\triangle d}{\triangle t}$

= $\frac{d_{60}-d_0}{60-0}$

= $\frac{90-0}{60-0}$

= 1.5 meter per second

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A straight trail with a uniform inclination of 15 degrees leads from a lodge at an elevation of 600 feet to a mountain lake at a

9966 [12]

Answer:

The length of the trail = 22796 ft

Explanation:

From the ΔABC

AC = length of the trail = x

AB = 6100 - 600 = 5500 ft

Angle of inclination $\theta$ = 15°

$\sin \theta = \frac{AB}{AC}$

$\sin 15 = \frac{5900}{x}$

$x = \frac{5900}{0.2588}$

x = 22796 ft

Since x = AC = Length of the trail.

Therefore the length of the trail = 22796 ft

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3 years ago

Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?

gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒ $\frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}$

On substituting the values, we get

⇒ $\frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}$

On taking L.C.M, we get

⇒ $\frac{1}{R_{net}} =\frac{2+1}{6}$

⇒ $\frac{1}{R_{net}} =\frac{3}{6}$

⇒ $\frac{1}{R_{net}} =\frac{1}{2}$

On applying cross-multiplication, we get

⇒ $R_{net}=2 \Omega$

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Answer:

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