Answer:
Magnitude of the average force = 7.85 N
Explanation:
Data given:
Mass of bullets, m = 6.4 g
Rate of bullets/min, r = 92 bullets/min
Speed of each bullet, v = 400 m/s
Change in momentum here, Δ B = Bf - Bi
where f is the final and i is the initial
Note that change in momentum = force X time
So, Δ B = m(vf - vi)
= 2mv
= 2 X 0.0064 kg X 400 m/s (convert g to kg)
= 5.12 kg.m/s (for one bullet)
so for the 92 bullets = 92 X 5.12 kg.m/s
= 471.04 kg.m/s
The force = Δ B ÷ Δt
where t = time measured in 60 seconds
= 471.04 kg.m/s ÷ 60 seconds
= 7.85 N
