Answer:
6. im not sure though
Step-by-step explanation:
because if he picks 4 orange and 3 are green, then it means you multiply by 2 because 4*2=8, SO 3*2=6. again, im not sure if its right or not.
3(a-b) and 3a-3b. Equivalent
2a(2+b) and 4ab. Not equivalent
Answer:
Step-by-step explanation:
Let's do the obvious things first.
Right rectangle
w = 11
L = 17
Formula
Area = L * W
Area = 11 * 17
Area = 187
Left rectangle
W = 8
L = 11
Area = 8 * 11= 88
Middle Rectangle
W = 11
L = 15
Area = 11 * 15 165
Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)
There are 2 triangles
Area = 2 * 1/2 * l1 * l2
Leg 1 = 8
Leg2 = 15
Area = 2 * 1/2 (8 * 15)
Area = <u> 120 </u>
Total = 120 + 165 + 88 + 187 = 560
Unless you have an E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.
Answer:
what do you need help with
Step-by-step explanation:
:)
Step-by-step explanation:
We have given,
A rational function : f(x) = 
W need to find :
Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.
For no values of x, we get indetermined form (i.e
), Hence there is no holes
Vertical Asymptotes:
Plug y=f(x) = ∞ in f(x) to get vertical asymptote {We can us writing ∞ =
}
i.e ∞ = 
or 
or x-4 =0
or x=4, Hence at x = 4, f(x) has a vertical asymptote
X -intercept :
Plug f(x)=0 , to get x intercept.
i.e 0 = 
or x - 2 =0
or x = 2
Hence at x=2, f(x) has an x intercept
Horizontal asymptote:
Plug x = ∞ in f(x) to get horizontal asymptote.
i.e f(x) =
= 
or f(x) = 
or f(x) = 1 = y
hence at y =f(x) = 1, we get horizontal asymptote