PLEASE HELP ON 35C ASAP. WILL MARK BRAINLIEST!!!! NEED BY TODAY ITS DUE!!! PLEASE!!! PLEASE HELP!!!

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

Answer: they all are congruent

b n/a c n/a

Step-by-step explanation:

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Cos^2 2x−cos^2 6x=sin4x sin8x<br> please help me prove it

Olin [163]

Cos² 2x = (1+cos 4x )/2
cos² 6x = (1+cos 12x)/2
subtract to get 1/2 (cos 4x - cos 12x )
= 1/2 (2 sin 4x sin 8x ) as cos A - cos B = 2 [ sin (A+B)/2 sin (A-B)/2 ]
so the answer

4 0

2 years ago

In the figure above, circles A and B are tangent to each other and to the large circle. If the radius of circle A

Ne4ueva [31]

Answer:

The answer to your question is A = 200.96 u²

Step-by-step explanation:

Data

Radius A = 6

Radius B = 2

π = 3.14

Area = ?

Formula

Area = πr²

Process

1.- Calculate the radius of the large circle

Radius = radius of circle A + radius of circle B

Radius = 6 + 2

Radius = 8

2.- Substitute in the formula

Area = (3.14)(8)²

Area = 3.14(64)

Area = 200.96 u²

6 0

3 years ago

given that the center of a circle is at point (-3,5) and that the radius of the circle is 6 units, write the the equation of the

Anika [276]

The equation of a cricle is
$(x-h)^{2}+(y-k)^{2}=r^{2}$
h being the x coordinate of the given point and k being the y coordinate of the given point (r also being the radius).

Now we have to plug the points into the equation
$(x--3)^{2} +(y-5)^{2} = 6^{2}$
now just simplify the the equation
$(x+3)^{2} +(y-5)^{2} = 36$

3 0

3 years ago

Perform the modular arithmetic. (7 · 15) (mod 4)

Reika [66]

We could do it by first writing

$7\cdot15=(4+3)\cdot(4+11)=4^2+14\cdot4+33$