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arlik [135]
3 years ago
12

Which expression is equivalent to -3(4x-2)-2x

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

d

Step-by-step explanation:

-3(4x+2)-2x

-12x+6-2x

-14x+6

andriy [413]3 years ago
8 0

Answer:

*error* error* This account is here to assist CodeName: ELA/ LANGUAGE ARTS/ ENGLISH. Please say RESET in order for me to go back to ELA/ LANGUAGE ARTS/ ENGLISH.

Step-by-step explanation:

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Oliver saves pennies and he saves the same number of pennies each week. His father gave him a jar of pennies to get him started.
Elodia [21]

Answer:b 150+40

Step-by-step explanation: i add 150+40 = 190 than i multiply 40 times the week so 13 and is 520 and than add 150 so its 670. :) your welcome

3 0
3 years ago
Use a quadratic equation to find two real numbers with a sum of -43 and a product of 306.
vlabodo [156]

Answer:

Real numbers = 39 and 9

Step-by-step explanation:

The standard form of a quadratic equation is ax² + bx + c = 0

Given the following data;

a = 1

b = -43

c = 306

Quadratic equation formula is;

x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}

Substituting into the equation, we have;

x = \frac {-(-43) \; \pm \sqrt {43^{2} - 4*1*306}}{2*1}

x = \frac {43 \pm \sqrt {1849 - 1224}}{2}

x = \frac {43 \pm \sqrt {625}}{2}

x = \frac {43 \pm 25}{2}

x_{1} = \frac {43 + 25}{2}

x_{1} = \frac {68}{2}

x_{1} = 39

x_{2} = \frac {43 - 25}{2}

x_{2} = \frac {18}{2}

x_{2} = 9

Therefore, the two real numbers are 39 and 9.

The quadratic equation now becomes;

x² - 43x + 306 = (x - 39)(x - 9) = 0

4 0
3 years ago
PLEASE HELP MEEEEE!!!!!
Scrat [10]

Answer:

I think it might be d

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, IM STUCK ON MOST OF THEM
azamat

Answer: look it up

Step-by-step explanation: Lollll

6 0
3 years ago
What is the length of a segment in the complex plane with endpoints at 4 + 2i and 7 – 2i?
ira [324]

Answer:

5

Step-by-step explanation:

The complex number 4 + 2i on the complex plane has coordinates (4,2) and the complex number 7 - 2i has coordinates (7,-2). Thus, the length of a segment in the complex plane with endpoints at 4 + 2i and 7 – 2i is

\sqrt{(4-7)^2+(2-(-2))^2}=\sqrt{(-3)^2+4^2}=\sqrt{9+16}=\sqrt{25}=5.

6 0
3 years ago
Read 2 more answers
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