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Schach [20]
3 years ago
11

How many electrons will be involved in a triple covalent bond

Chemistry
1 answer:
valina [46]3 years ago
8 0
6 electrons

make me brainliest please.
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A 3L sample of an ideal gas at 178 K has a pressure of 0.3 atm. Assuming that the volume is constant, what is the approximate pr
harina [27]

Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

Explanation:

Given: T_{1} = 178 K,      P_{1} = 0.3 atm

T_{2} = 278 K,           P_{2} = ?

According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.

Formula used to calculate the pressure is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\

Substitute the values into above formula is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{0.3 atm}{178 K} = \frac{P_{2}}{278 K}\\P_{2} = 0.468 atm

Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

3 0
3 years ago
Elements are distinguished from each other by the number of protons present in their nuclei??
Kisachek [45]

False....................

7 0
3 years ago
Atom , classify it<br><br><br><br><br>helppoppppoeowiie​
timama [110]

Answer:

A atom is a small unit to which matter can be divided without releasing electrically charged particles

Explanation:

5 0
3 years ago
Please help me I will give you extra points and the brain thing please actually do it.
Shkiper50 [21]
Inertia is the retaliation of an object to change in its velocity
4 0
3 years ago
A hot air balloon starts with its temperature at 68.7°C and a pressure of 0.987 ATM and volume of 564L at what temperature in de
ICE Princess25 [194]

Answer:

54.7°C is the new temperature

Explanation:

We combine the Ideal Gases Law equation to solve this.

P . V = n. R. T

As moles the balloon does not change and R is a constant, we can think this relation between the two situations:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

T° is absolute temperature (T°C + 273)

68.7°C + 273 = 341.7K

(0.987 atm . 564L) / 341.7K = (0.852 atm . 625L) / T₂

1.63 atm.L/K = 532.5 atm.L / T₂

T₂ = 532.5 atm.L / 1.63 K/atm.L → 326.7K

T° in C = T°K - 273 → 326.7K + 273 = 54.7°C

3 0
3 years ago
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