Answer:

Step-by-step explanation:
Please refer to the attached figure for the labeling and construction in the given figure:
Given that minor angle of arc AB is
.
Or in other words, we can say that angle subtended on the center O by the arc is
.
Now, PA and PB are the tangents so, if we join the center of circle O with A and B, the angles formed are right angles.
i.e.

Now, we know that sum of internal angles of a quadrilateral is equal to
.
Here, we have the quadrilateral AOPB.

Hence, the correct answer is:

300=15x
x=20 weeks
The third equation
w=20 weeks
A percentage is out of 100%.
19 (questions right) / 28 (total) = 0.67857142857
Round to the tenth, 67.9.
<h2>
67.9%, not a passing score.</h2>
All that is needed is for you to graph the points and if they form a line, they will be collinear. If not, they will not be collinear.