3 years ago

Kepler's third law can be used to compare the moon's orbit around the earth to the orbit of the earth around the sun.

Physics

1 answer:

Pavlova-9 [17]3 years ago

5 0

No, you can't! The planet should rotate around a common body!

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A 20kg bike accelerates at 10 m/s2. With what force was the person padeling?

Romashka-Z-Leto [24]

Formula:
F = ma
F: force (N) m: mass (kg) a: acceleration (m/s^2)

Solution:
F = ma
F = 20 × 10
= 200N

6 0

3 years ago

A drawback of burning biomass to produce electricity is that it is ___.

attashe74 [19]

Answer: Unsustainable wood harvesting can lead to deforestation, soil erosion, and desertification.

Explanation: you welcome

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2 years ago

Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t

-Dominant- [34]

The load is the weight of the rock that Jonathan lifts:
$L=3000 N$
The effort instead is the force applied in input to the lever in order to lift the rock:
$E=300 N$

So, the ratio between load and effort for this exercise is
$\frac{L}{E}= \frac{3000 N}{300 N}=10$
So, the ratio is 10:1.

3 0

2 years ago

three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively,

ioda

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

$C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF$

Capacitance of capacitor 2,

$C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF$

Capacitance of capacitor 3,

$C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF$

(b) The equivalent capacitance in series combination is :

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF$

Hence, this is the required solution.

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3 years ago

What is the gravitational potential energy of a 15.0kg object that is 5.00m above the ground relative to a point 8.00m above the

Licemer1 [7]

Explanation:

an object's gravitational potential energy Eg is m×g×h where:

m=mass

g=9.8m/s²

h=height relative to the closest object below it (because it cannot potentially fall through it

so Eg = 15×9.8×5=735J

4 0

1 year ago