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3 years ago

10

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.46. The weight of the object

is 90N. What is the force of friction?

1 answer:

DaniilM [7]3 years ago

4 0

Answer:

the friction force is 41.4N

Explanation:

from f=μ R, where R is the normal reaction. this is equal to the weight of the object

therefore, f = 0.46*90 = 41.4 N

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A quarterback back pedals 3.3 meters southward and then runs 5.7 meters northward. For this motion, what is the distance moved?

mixas84 [53]

Answer:

The distance moved is 9 meters

The magnitude of the displacement is 2.4 meters

The direction of the displacement is northward

Explanation:

- <em><u>Distance</u></em> is the length of the actual path between the initial and the

final position. Distance is a scalar quantity

- <u><em>Displacement</em></u> is the change in position, measuring from its starting

position to the final position. Displacement is a vector quantity

The quarterback pedals 3.3 meters southward

That means it moves down 3.3 meters

Then runs 5.7 meters northward

That means it runs up 5.7 meters

The distance = 3.3 + 5.7 = 9 meters

<em></em>

<em>The distance moved is 9 meters</em>

It moves southward (down) for 3.3 meters and then moves northward

(up) for 5.7

It moves from zero to 3.3 down and then moves up to 5.7

The displacement = 5.7 - 3.3 = 2.4 meters northward

<em />

<em>The magnitude of the displacement is 2.4 meters</em>

<em>The direction of the displacement is northward</em>

8 0

3 years ago

1. A 100-kg crate is pulled across a warehouse floor using a rope with a force of 250 N at an angle of 45o from the horizontal.

harkovskaia [24]

Answer:

(a) The net force is 80.394 N

The acceleration of the crate is 0.804 m/s²

(b) the final velocity of the crate is 5.02 m/s

Explanation:

Given;

mass of the crate, m = 100 kg

applied force, F = 250 N

angle of inclination, θ = 45°

coefficient of friction, μ = 0.12

Applied force in y-direction, $F_y = Fsin \theta = 250sin45 = 176.78 \ N$

Applied force in x-direction, $F_x = Fcos \theta = 250cos45 = 176.78 \ N$

The normal force is calculated as;

N + Fy -W = 0

N = W - Fy

N = (100 x 9.8) - 176.78

N = 980 - 176.78 = 803.22 N

The frictional force is given by;

Fk = μN

Fk = 0.12 x 803.22

Fk = 96.386 N

(a) The net force is given by;

$F_{net} = F_x - F_k\\\\F_{net} = 176.78-96.386\\\\F_{net} = 80.394 \ N$

Apply Newton's second law of motion;

F = ma

$a = \frac{F_{net}}{m}\\\\ a = \frac{80.394}{100}\\\\ a = 0.804 \ m/s^2$

(b) the velocity of the crate after 5.0 s

$F = ma= \frac{m(v-u)}{t} \\\\Ft =m(v-u)\\\\v-u = \frac{Ft}{m}\\\\ v = \frac{Ft}{m} + u\\\\v = \frac{F_{net}*t}{m} + u\\\\v = \frac{80.394*5}{100} + 1\\\\v = 5.02 \ m/s$

7 0

3 years ago

in a lever, a load of 600N is lifted by using 400 effort. If the load is at the distance of 20cm and the effort at the distance

koban [17]

Explanation:

Load (l) = 680N

Effort (E) = 500N

Length slope (l) = 12m

Height slope (h) = 8 m

Output = load * height

680 *8 = 5.44 *103 J

The Input = effort * length = 500 *12 = 6000J

the Mechanical advantage (M.A) = load effort= 600500=1.36

the Velocity ratio (V.R) =lh=128 = 1.5

the Efficiency =M.A100%V.R= 90.6%

8 0

3 years ago

What is the current in a series circuit with a resistance of 30 ohms and a potential difference of 120 volts?

mars1129 [50]

0.25A....................

7 0

3 years ago

Which poison was used in the Jonestown massacre?

olga nikolaevna [1]

That would be Cyanide.

Hope this helps! (:

3 0

3 years ago

Read 2 more answers