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Talja [164]
2 years ago
9

last minute forgot to do it please help and do all of them and I have one more I promise I’ll give you good ratings :D

Mathematics
1 answer:
Zolol [24]2 years ago
5 0

1.) The error is that she attached the

variable with the flat fee (which is

constant) and put the daily rent as a

constant (which is variable).

The correct equation is:

365+125x=250+175x

2.) N=5

3.) k=-35.

Explanation: Solution:

17k-6=37k+4 . 17k-37k=4+6 .

-27k=10 . k=10\cdot(7-2) . k=-35 .

4.)

y =   - \frac{9}{16}

.

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How can you generate x-3y+5 from the expression x+y+4+2y+1
vladimir2022 [97]

Answer: Here is the explanation. also it it +3y not -3y

Step-by-step explanation:

x+y+4+2y+1=x+3y+5 because

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now you have: x+3y+5

if you do not understand, What i am trying to say is, you need to add all of the same things.

3 0
3 years ago
Find the dicontinuities of the function.
elena-s [515]

Answer:

Step-by-step explanation:

I'm assuming you meant to type in

f(x)=\frac{x^2+12x+27}{x^2+4x+3} because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to

f(x)=\frac{(x+3)(x+9)}{(x+1)(x+3)} and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.

The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!

5 0
3 years ago
For the following exercises, find (f ∘ g)(x) and (g ∘ f)(x) for each pair of functions.
Rufina [12.5K]

Answer:

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Step-by-step explanation:

It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$.

To find $(f \circ g)(x)$, substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$, substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$$

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Solve by the linear combination method.
wlad13 [49]

X=5/9

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See below the following picture for the solution

7 0
3 years ago
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