Ask question

Ask question

All categories

3 years ago

14

If Sergio has 16 quarters and dimes in his pocket, and they have a combined value of 265 cents, how many of each coin does he ha

ve?

1 answer:

Mandarinka [93]3 years ago

8 0

9 dimes and 7 quarters. Each quarter is 25 cents and each dime is 10 cents. 25 x 7 = 175, 10 x 9 = 90. Add 175 and 90 together and it gives you 265.

You might be interested in

Find the roots. Answer the question below.

12345 [234]

Answer:

roots: -4 and 7

Step-by-step explanation:

where the graph crosses the x axis is where the roots are located

8 0

3 years ago

What is the answer (6-1+7) =

sdas [7]

Answer:

12

Step-by-step explanation:

You do what's in parentheses first, but everything is in parentheses so it's pretty much ineffective. In PEMDAS, addition and subtraction are coupled so you do them left to right. 6-1 is 5 and 5+7 is 12.

4 0

3 years ago

Read 2 more answers

I need help! Jeff sold half of his comic book collection. Two years later he decides to start collecting again. After buying 12

mylen [45]

Answer:

23 comics before

5 0

3 years ago

A bag contains 7 red marbles, 5 blue marbles, and 2 green marbles. What is the probability of choosing a blue marble when one ma

blsea [12.9K]

Answer:

a red

Step-by-step explanation:

A bag contains 7 red marbles, 5 blue marbles, and 2 green marbles. What is the probability of choosing a blue marble when one marble is drawn?

6 0

3 years ago

Read 2 more answers

1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn

alisha [4.7K]

Answer and explanation:

Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.

To find : Determine each of the following,

a) $(A\cap B)\cap C$

b) $(A\cup B)\cap (A\cup C)$

c) $A - (B\cup C)$

d) $(A-C) (C-A)$

Solution :

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.

The intersection of two sets is a new set that contains all of the elements that are in both sets.

a) $(A\cap B)\cap C$

$A\cap B=\{1,4,5\}$

Then, $(A\cap B)\cap C=\{4\}$

b) $(A\cup B)\cap (A\cup C)$

$A\cup B=\{1,2,3,4,5,7,8,9\}$

$A\cup C=\{1,2,3,4,5,7,9\}$

$(A\cup B)\cap (A\cup C)=\{1,2,3,4,5,7,9\}$

c) $A - (B\cup C)$

$B\cup C=\{1,2,4,5,6,7,8,9\}$

$A - (B\cup C)=\{3\}$

d) $(A-C) (C-A)$

$A-C=\{1,3,5\}$

$C-A=\{6,7,9\}$

$(A-C) (C-A)=\{1,3,5\}\times\{6,7,9\}$

$(A-C) (C-A)=\{(1,6),(1,7),(1,9),(3,6),(3,7),(3,9),(5,6),(5,7),(5,9)\}$

5 0

3 years ago