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vladimir2022 [97]
3 years ago
15

Evaluate the following expression when x = 1 and y = 2 and z = 6 -3y2-4y + 5

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

-15

Step-by-step explanation:

-3(2)2-4(2)+5

-12-8+5

-20+5

5-20= -15

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Please help me in alegbra! :(
nika2105 [10]

Answer:

1) 4

2) 1

3) -7

4) 13

Step-by-step explanation:

Instructions:

a) Subtract or add the slope from each side

( it doesn't matter which one you pick )

b) Subtract or add the # next to the slope from each side

( it doesn't matter which one you pick )

c) Divide Each number by the slope

d You have you answer

____________________________________________

1) 9x - 35 = - 7x + 29

+7x + 7x

_____________________

16x - 35 = 29

+ 35 +35

_____________________

16x = 64

_____________________

16 16

x = 4

2). - 2x - 2 = 9x - 13

+2x +2x

_____________________

- 2 = 11x - 13

+ 13 + 13

_____________________

11 = 11x

_____________________

11 11

1 = x

3). 3x + 29 = - 5x - 27

+5x + 5x

_____________________

8x + 29 = - 27

-29 -29

_____________________

8x = -56

_____________________

8 8

x = -7

4). x - 11 = 3x - 37

- x - x

______________________

-11 = 2x - 37

+37 +37

______________________

26 = 2x

_______________________

2 2

13 = x

Hope this helps! (:

3 0
3 years ago
How??????????????????????????????????????!?????????
maks197457 [2]
Try describing the amount of numbers in the square u know like "shade covers 2/4 of the square''
3 0
3 years ago
Write an expression for the calculation double the number six and then subtract 36÷12
andreev551 [17]

Hello there friendo.

I believe the correct answer to your question would be (2*6) - (36/12).

I hope this can help you! :)

6 0
3 years ago
PLS ANSWER QUICK LOL
Setler [38]

(3j, 3k) and (3/j, 3k)

So if their x values have the same signs and their y values have the same signs, they are in the same quadrant.

If j is negative, both 3j and 3/j would be negative. If j is positive then both 3j and 3/j are positive.

And 3k is the same as 3k.


5 0
4 years ago
Read 2 more answers
Two planes just took off from Charlotte NC. The first plane is traveling 1.5 times as fast as the second plane. After traveling
Ksju [112]

Givens

Slower plane

r = r

t = 2.5 hours

d = d

Faster Plane

r_faster = 1.5 * r

t = 2.5 hours

d1 = d + 127.5

The  time is the same for both

t = d/r

d1/r1 = d/r

(d+ 127.5)/1.5r = d/r   Multiply each side by r

(d + 127.5)/1.5 = d       Multiply both sides by 1.5

d + 127.5 = 1.5d          Subtract d from both sides.

127.5 = 1.5d - d    

127.5 = 0.5d              Divide by 0.5

127.5 / 0.5 = d

255 = d

Now you can go back and figure out the rates.

First find d1

d1 = d + 127.5

d1 = 255 + 127.5

d1 = 382.5

<em><u>Rate of the slower plane</u></em>

d = 255

t = 2.5 hours

r = d/t

r = 255/2.5

r = 102 miles per hour.

<em><u>Faster plane</u></em>

d1 = 382.5 miles

t = 2.5 hours

r1 = d/t

r1 = 382.5/2.5 = 153 miles per hour.


5 0
3 years ago
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