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max2010maxim [7]

3 years ago

6

An increase in pressure increasing the boiling point of a liquid is an example of a- physical property b-chemical property c-phy

sical change d- chemical changcgre

1 answer:

bazaltina [42]3 years ago

3 0

Answer:

Ans. C. physical change

Explanation:

Physical: boiling and melting are physical changes. When water boils no bonds are broken or formed.

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What is the density of CO gas if 0.196 occupies a volume of 100 no

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3 years ago

If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density

adelina 88 [10]

Explanation:

The given data is as follows.

Mass = 27.9 g/mol

As we know that according to Avogadro's number there are $6.023 \times 10^{26}$ atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

1 atoms weight = $\frac{38}{6.023 \times 10^{26}}$

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

Therefore, total weight of atoms in a unit cell will be as follows.

= $\frac{8 \times 27.9 g/mol}{6.023 \times 10^{26}}$

= $37.06 \times 10^{-26}$

Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

= $a^{3}$

= $(0.503 \times 10^{-9})^{3}$

= $0.127 \times 10^{-27} m^{3}$

Formula to calculate density of diamond cell is as follows.

Density = $\frac{mass}{volume}$

= $\frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}$

= 2918.1 $g/m^{3}$

or, = 0.0029 g/cc (as 1 $m^{3} = 10^{6} cm^{3}$ )

Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.

4 0

3 years ago