An important Similarly between photosynthesis and cellular respiration is that both process

Chemistry

1 answer:

adelina 88 [10]3 years ago

7 0

Answer:

Similarity between photosynthesis and cellular respiration is that both process :

Involve production of energy

Exchange of gases

Goes through electron chain reactions

Explanation:

Photosynthesis : It is the process in which green plants containing chlorophyll prepare their food in the presence of Sunlight , water and carbon dioxide.This process occur inside chloroplast .

Here Food is prepared.Oxygen and food is produced as a result of photosynthesis .

The electrons triggers the reaction of food formation.

Energy is released during photosynthesis.

Gaseous exchange between CO2 and O2 occur.

Respiration :

It is the process in which living organism converts oxygen and food to water and carbon dioxide . Here energy is released in the form of ATP. It take place inside the mitochondria of the cell.

Exchange of Gases occur between organism and environment.

Here , mitochondrial electron transport occurs to produce ATP.

Hence , similarity between photosynthesis and cellular respiration is that both process:

Involve production of energy

Exchange of gases(carbon dioxide and oxygen)

Goes through electron chain reactions

You might be interested in

17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI

galina1969 [7]

Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: $M_{1}$ = 0.20 M, $V_{1}$ = 15.0 mL

$M_{2}$ = 0.10 M, $V_{2}$ = ?

Formula used is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula s follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL$

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

4 0

2 years ago

A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati

prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$