The amount of matter in an object is its ____ weight mass volume density

Nebulae are enormous clouds in outer space.they are made mostly of hydrogen gas ,helium gas and dust , some nubelae glow brightl

adell [148]

They’re different in regards to the fact that nebulae are not actively burning while stars are

3 0

3 years ago

Heterogeneous non example

Bogdan [553]

Heterogeneous 'mixtures' (because they don't meet the definition of mixtures) are mixtures substances that aren't completely uniformly spread out. They haven't reacted with the solvent to become a solution.

Explanation: There are 2 types of heterogeneous solutions, A Colloid and a suspension.

Colloid: You can check if a mixture is heterogeneous by passing a light ray through it. This may cause the Tyndall effect (If the mixture is a colloid) when the Colloidal Heterogeneous mixture's particles are so small that they refract the beam of light and the path of light will be visible, like if you add 3 drops of milk in a glass of Water and shine a laser light through it. This is because the particles are too small to be seen by the unaided eye but big enough to scatter you laser light. However that particles won't settle down or will be separated by a filter paper due to particles' small size.

Suspension: A solution will be a solution when the particles of the Mixture is big enough to be seen by the unaided eye. Like if you mix sand and Water, the sand will eventually settle down due to Gravity. The mixture's solute will be big enough to pass through a filter paper.

8 0

4 years ago

The specific heat of a certain type of cooking oil is 1.75 j/(g·°c). how much heat energy is needed to raise the temperature of

love history [14]

The energy needed to raise the temperature of 2.83 kg of the oil from 23 to 191 is calculated using Mc delta T formula

M= mass ( 2.83 Kg to grams = 2.83 x1000= 2830 grams)
C= specific heat capacity = 1.75 j/g/c
delta T= change in temperature = 191- 23 = 168 c

heat energy = 1.75 j/g/c x 2830 g x 168 c= 832020 J

5 0

4 years ago

A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?

Elodia [21]

Answer: The mole fraction of barium chloride in the solution is 0.024

Explanation:

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.