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zzz [600]
3 years ago
15

If an object has a density of 1.35 g/ml ,will it float or sink in water?

Chemistry
2 answers:
wolverine [178]3 years ago
8 0

Answer:

It wil sink in water.

Explanation:

The law of bouyancy states that objects with lower densitiy than the liquid they´re submerged in will float, and if the object has a density of 1.35 g/ml, it wil sink in water because the density of water is 1g/ml, so because of the law of bouyancy and because the object has a greater density than water, when submerged in water the object will sink.

AleksAgata [21]3 years ago
7 0
Water has a density of 0.9982 g/mL, so it will sink.
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Is warm water or cold water more dense
diamong [38]
Cold water is denser
8 0
3 years ago
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Which of the following buffers will be most effective at pH 9.25? Group of answer choices a mixture of 1.0 M HC2H3O2 and 1.0 M N
ludmilkaskok [199]

Answer:

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

Explanation:

Step 1: Data given

pH of a buffer = pKa + log ([A-]/[Ha])

a mixture of 1.0 M HC2H3O2 and 1.0 M NaC2H3O2 (Ka for acetic acid = 1.8 x 10-5)

pH = -log( 1.8 * 10^-5) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 4.74

a mixture of 1.0 M NaCN and 1.0 M KCN (Ka for HCN = 4.9 x 10-10)

pH = -log( 4.9 * 10^-10) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 9.30

a mixture of 1.0 M HCl and 1.0 M NaCl

The solution made from NaCl and HCl will NOT act as a buffer.

HCl is a strong acid while NaCl is salt of strong acid and strong base which do not from buffer solutions hence due to HCl PH is less than 7.

a mixture of 1.0 M NH3 and 1.0 M NH4Cl (Kb for ammonia = 1.76 x 10^-5)

Ka * Kb = 1*10^-14

Ka = 10^-14 / 1.76*10^-5

Ka = 5.68*10^-10

pH = -log( 5.68*10^-10) + log (1/1)

pH = -log( 5.68*10^-10)

pH = 9.25

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

8 0
3 years ago
The first task you are assigned in your summer laboratory job is to prepare a concentrated naoh stock solution. the molecular we
tensa zangetsu [6.8K]

240 g NaOH

<em>Step 1</em>. Calculate the moles of NaOH

Moles of NaOH = 0.750 L solution × (8 mol NaOH/1 L solution) = 6 mol NaOH

Step 2. Calculate the mass of NaOH

Mass of NaOH = 6 mol NaOH × (40 g NaOH/1 mol NaOH) = 240 g NaOH

7 0
3 years ago
Non-ferrous alloys do not contain <br> a. copper. <br> b. brass. <br> c. gold. <br> d. iron.
Elena L [17]
Iron is the correct answer
4 0
3 years ago
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A cup of gold colored metal beads was measured to have a mass 425 grams. By water displacement, the volume of the beads was calc
Troyanec [42]

Given parameters;

Mass of gold colored metal beads  = 425g

Volume of water displaced by beads = 48.0cm³

Unknown;

Identity of the metal = ?

Given densities;

Gold: 19.3 g/mL

Copper: 8.86 g/mL

Bronze: 9.87 g/mL

Density is an intensive property of any substance. This implies that we can use the density of any substance to identify it.

Density can be defined as the mass per unit volume of a substance. Every substance has a unique mass per volume.

 Mathematically;

                    Density  = \frac{mass}{volume}

where mass is in kg or g

           volume is in  m³ or cm³

To find the density, we must know the mass and volume.

In this problem, the volume of the gold metal beads is the same as the volume of water displaced. This is a way to measure volume of solids.

Since the volume is given in cm³, and we are comparing with choices that have units in g/mL, we simply convert the volume in cm³ to mL

                   1cm³  = 1mL³

So therefore, volume of gold colored metal is 48mL

Now input the parameters given and solve for the density;

           Density  = \frac{425g}{48mL }    = 8.85g/mL

From the given densities, we clearly see that copper is the metal since they both of similar densities.

4 0
3 years ago
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