Answer:
7. 3–ethyl–6 –methyldecane
8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene
Explanation:
It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.
The name of the compound given in the question above can be written as follow:
7. Obtaining the name of the compound.
Compound contains:
I. Decane.
II. 3–ethyl.
III. 6 –methyl.
Naming alphabetically, we have
3–ethyl–6 –methyldecane
8. Obtaining the name of the compound.
Compound contains:
I. 2,2–dimethyl.
II. 4–propyl.
III. 4 –heptene.
IV. 5–ethyl.
Naming alphabetically, we have
5–ethyl–2,2–dimethyl–4–propyl–4 –heptene
U-238 has 92 protons, 146 neutrons, and 92 electrons.
Rn-222 has 86 protons, 136 neutrons, and 86 electrons.
U-238 is Uranium 238 and Rn-222 is Radon 222.
<span>C12H22O11. If it is a dehydration reaction, there is a union of the two monosaccharides and a water molecule is lost. So double the C6H12O6, and remove an H2O, so C12H24O12 - H2O would yield C12H22O11.</span>
The phase in which water molecules form crystal lattice is : B. Freezing
When water undergone a freezing phase, it will trapped a specific amount of Gases inside it. Crystal lattice is basically the gas molecule that trapped within the water
hope this helps
