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gizmo_the_mogwai [7]
3 years ago
6

Look at the cups shown below (images are not drawn to scale):

Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

14.7 cubic inches


Step-by-step explanation:

<em><u>**Figure are not shown but from description, here is the solution**</u></em>


Volume of a cone = \frac{1}{3}\pi r^2h

Where

  • r is the radius
  • h is the height

Volume of Cylinder = \pi  r^2h

Where

  • r is the radius
  • h is the height

<u>Note:</u> In this problem, the width is given, it is same as diameter. Since radius is half of that, radius is half of width.


Volume of the cone = \frac{1}{3}\pi  (1)^2(4)=4.2

Volume of Cylinder = \pi (1)^2(6)=18.8


So the Cylinder will hold 18.85-4.19=14.66=14.7 more than Cone.

Hence, Cup B will hold 14.7 cubic inches of juice more than Cup A.

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A regulation basketball has a diameter of about 9 in. What is the best approximation for the volume of this ball? 3050 in³ 382 i
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The best apporximation for the volume of this ball is 382 cubic inches.

<h3>What is the volume of the ball?</h3>

The volume of the ball is calculated by the formula V = 4 / 3πr³. This formula is the same in the whole world.

Given

A regulation basketball has a diameter of about 9 in.

The radius of the ball is;

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The volume of the ball is;

\rm Volume =\dfrac{4}{3}\pi r^3\\\\Volume=\dfrac{4}{3} \times 3.14 \times 4.5^3\\\\Volume =\dfrac{144.53}{3}\\\\Volume = 381.51\\\\Volume = 382 \ In^3 \ apporx

Hence, the best apporximation for the volume of this ball is 382 cubic inches.

To know more about volume click the link given below.

brainly.com/question/10647788

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