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cestrela7 [59]
3 years ago
11

After a polypeptide chain has been synthesized, certain amino acids in the peptide may become modified. For each modified amino

acid, identify the standard amino acid from which it is derived. Enter the unabbreviated name of the standard amino acid. The amino acid structure shows the fully ionized form. The side chain is C H 2, C H 2, C H (O H), C H 2, N H 3 (plus). standard amino acid: Identify the modification that yields the first amino acid depicted.
Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:

The name of the amino acid is lysine.

The number five carbon in lysine is the carbon that is hydroxylated. The modification you ask is when adding hydroxyl group (C-OH bonds). These links are made by an enzyme called hydroxylase, vitamin C acting as a cofactor. This reaction is one of the most fundamental post-translational modifications.

Explanation:

AnnZ [28]3 years ago
5 0

Answer:

The modification that yields the first amino acid depicted is lysine

Explanation:

Lysine being an amino acid used in preparation of various medicine. It is used to prevent cold as well as sore throat, which is found to be caused by the herpes simplex labialis. It can be used orally or can be directly applied over the skin. various foods have lysine in it and they are meat, cheese, certain fishes, eggs, soybeans, spirulina and also fenugreek seed. They are the building block for the protein particles.

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PLS HELP THE QUESTION IS ON THE PICTURE
IceJOKER [234]

<u>Concepts used:</u>

1 mole of an element or a compound has 6.022 * 10²³ formula units

So, we can say that: <em>Number of formula units = number of moles * 6.022*10²³</em>

number of moles of an element or a compound = given mass/molar mass

<u>__________________________________________________________</u>

<u>003 - </u><u>Number of CaH₂ formula units in 6.065 grams</u>

Number of Moles:

We know that the molar mass of CaH₂ is 42 grams/mol

Number of Moles of CaH₂ = given mass/molar mass

Number of moles = 6.065 / 42

Number of moles = 0.143 moles

Number of Formula units:

Number of formula units = number of moles * 6.022*10²³

= 0.143 * 6.022 * 10²³

= 0.86 * 10²³ formula units

__________________________________________________________

<u>004 </u><u>- Mass of 6.34 * 10²⁴ formula units of NaBF₄</u>

Number of Moles:

We mentioned this formula before:

<em>Number of formula units = number of moles * 6.022*10²³</em>

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variable

Number of moles = 6.34 * 10²⁴ / 6.022*10²³

Number of moles=  10.5 moles

Mass of 10.5 moles of NaBF₄:

Molar mass of NaBF₄ = 38 grams/mol

Mass of 10.5 moles = 10.5 * molar mass

Mass of 10.5 moles = 10.5 * 38

Mass = 399 grams

__________________________________________________________

<u>005</u><u> - Number of moles in 9.78 * 10²¹ formula units of CeI₃</u>

Number of Moles:

We have the formula:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles   OR   0.016 moles

3 0
3 years ago
A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?
melomori [17]
[OH-]: <span>0.0063095734448</span>
7 0
3 years ago
Read 2 more answers
Calculate the volumeof 1.0M NaOH necessary to completely neutralize 100mL of 0.50M of phosphoric acid (H3PO4)?
blondinia [14]

Answer:

50 mL

Explanation:

In case of titration , the following formula is used -

M₁V₁ = M₂V₂

where ,

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V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ =  0.50M

V₁ = 100 mL

M₂ =  1.0M

V₂ = ?

Using the above formula , the volume of base , can be calculated as ,

M₁V₁ = M₂V₂

substituting the respective values ,

0.50M * 100 mL =  1.0M * V₂  

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3 0
3 years ago
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Sergeeva-Olga [200]

Answer:

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Explanation:

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The ability to travel great distances in the shortest time was achieved by which invention?
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By space travel.

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