Answer:
1. The new volume is 14L
2. The volume decreased
Explanation:
Step 1:
Data obtained from the question.
Initial Volume (V1) = 14.2 L
Initial pressure (P1) = 102.5 kPa
Initial temperature (T1) = 33°C
Final pressure (P2) = 100.9 kPa
Final temperature (T2) = 24°C.
Final volume (V2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature. This is illustrated below:
K = °C + 273
T1 = 33°C = 33°C + 273 = 306K
T2 = 24°C = 24°C + 273 = 297K
Step 3:
Determination of the new volume.
Applying the general gas equation P1V1/T1 = P2V2/T2, the new volume can be obtain as follow:
P1V1/T1 = P2V2/T2
102.5 x 14.2/306 = 100.9 x V2/297
Cross multiply to express in linear form as shown below:
306 x 100.9 x V2 = 102.5 x14.2 x297
Divide both side by 306 x 100.9
V2 = (102.5x14.2x297)/(306 x 100.9)
V2 = 14 L
The new volume is 14 L.
Step 4:
Determination of the change in volume. This is illustrated below
Final volume (V2) = 14 L
Initial volume (V1) = 14.2 L
Change in volume (ΔV) =?
Change in volume (ΔV) = Final volume (V2) - Initial volume (V1)
ΔV = V2 - V1
ΔV = 14 - 14.2
ΔV = - 0.2L
Since the change in volume is negative, it means there is a decrease in the volume.
