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Alecsey [184]
3 years ago
13

HELP! Which of the following fossils is an example of permineralization?

Chemistry
2 answers:
UNO [17]3 years ago
7 0

Answer:

Examples of permineralization

Most dinosaur bones are permineralized. Petrified wood: Permineralization is the first step in petrification.

saw5 [17]3 years ago
6 0

Answer: you didn’t put any picture of any answers to pick but example of permineralization fossils would be dinosaur remains and wood

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The smallest part of a compound that still acts like that compound is ____.
Leokris [45]
It is a molecule of the compound.
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A water bath in a physical chemistry lab is 1.75 m long, 0.730 m wide, and 0.650 m deep. If it is filled to within 2.27 inches f
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It is 0.720 meters cause if the manufacturers of liters contain 2.27 inches it would make a deeply filled of 0.660
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Number of electrons for all of these even the ones with a number by them ? Will give brainlist!!!!
Bumek [7]

Explanation:

s=2

p=6

d=10

f=14

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7 0
2 years ago
Unit 1- Unit Assessment (Matter & Density)
konstantin123 [22]

Answer:

<h3>The answer is 11 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 3025 g

volume = 275 mL

We have

density =  \frac{3025}{275}  \\

We have the final answer as

<h3>11 g/mL</h3>

Hope this helps you

7 0
2 years ago
When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
algol [13]

Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
2 years ago
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