Answer:
percentage yield of NaCl = 96.64%
Explanation:
The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:
NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is
NaHCO3 + HCl → NaCl + H2O + CO2
The question ask us to calculate the percentage yield of NaCl.
The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3
as
1 mole of NaHCO3 produces 1 mole of NaCl
Therefore,
molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g
molar mass of NaCl = 23 + 35.5 = 58.5 g
1 mole of NaHCO3 = 84 g
1 mole of NaCl = 58.5 g
since 84 g of NaHCO3 produces 58.5 g of NaCl
10 g of NaHCO3 will produce ? grams of NaCl
cross multiply
Theoretical yield of NaCl = (10 × 58.5)/84
Theoretical yield of NaCl = 585/84
Theoretical yield of NaCl = 6.9642857143 g
percentage yield of NaCl = actual yield/theoretical yield × 100
percentage yield of NaCl = 6.73/6.9642857143 × 100
percentage yield of NaCl = 673/6.9642857143
percentage yield of NaCl = 96.635897436%
percentage yield of NaCl = 96.64%
