All categories

3 years ago

HURRY ! the BEST I will give the brainliest

Physics

1 answer:

Oksanka [162]3 years ago

7 0

~Hello There!~

$v^{2} =u^{2} +2as$

$a = \frac{v-u}{t}$

$40^{2} =2(\frac{40-0}{8})s$

$1600 = 10s$

$s = 160$

s = distance traveled til car stopped.

180 - 160 = 20

The distance of stopped car from obstacle is 20m

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

You might be interested in

A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A

Kruka [31]

Answer:

$\omega_f = 585.37 \ rev/s$

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)= 800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

$I \omega_i = I' \omega_f$

$(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f$

$M\times 800 = ( M + m )\omega_f$

$3\times 800 = (3+1.1)\times \omega_f$

$2400 = (4.1)\times \omega_f$

$\omega_f = 585.37 \ rev/s$

3 0

3 years ago

1. Una pelota rueda hacia la derecha siguiendo una trayectoria en línea recta de modo que recorre una distancia de 10m en 5 s ,

devlian [24]

Answer:

https://youtu.be/ymHHdoCGJOU

8 0

3 years ago

Which ecosystem has the most biodiversity? How do you<br> know?

Bezzdna [24]

Answer:

ecosystem B

Explanation:

because it goes through more animal's and is correct

8 0

3 years ago

Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec

SOVA2 [1]

Answer:

$F_{net} = 6.879\times 10^{- 7}\ N$

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

$F_{net} = F + F'$

$F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N$

6 0

3 years ago

Alona [7]

In the circuit, the total current is 60 A and the voltage is 240 V. If R1

resistance is 20 Ω, then the R2 resistance would be 5 Ω

<h3>What is resistance?</h3>

Resistance is the obstruction of electrons in an electrically conducting material. The SI unit of the resistance is Ohm

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

where V is the voltage

I is the current

R is the resistance

For the given problem V= 240 V and I = 60 A

R = V/I

R =240/60

R =4 Ω

For calculating equivalent resistance in parallel combination.

1/Re = 1/R1 + 1/R2

1/4 = 1/20 + 1/R2

R2 = 5 Ω

Thus , the R2 resistance would be 5 Ω, therefore the correct answer is option B.

Learn more about resistance here

brainly.com/question/14547003

#SPJ1

7 0

1 year ago

HURRY ! the BEST I will give the brainliest​

HURRY ! the BEST I will give the brainliest