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ddd [48]
3 years ago
8

HURRY ! the BEST I will give the brainliest​

Physics
1 answer:
Oksanka [162]3 years ago
7 0

~Hello There!~

v^{2} =u^{2} +2as

a = \frac{v-u}{t}

40^{2} =2(\frac{40-0}{8})s

1600 = 10s

s = 160

s = distance traveled til car stopped.

180 - 160 = 20

The distance of stopped car from obstacle is 20m

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

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Se lanza verticalmente hacia arriba un cuerpo que para por un punto A con una rapidez de 54 m/s y por otro punto B situado mas a
Brut [27]

1) The time taken is 3.06 s

2) The distance between the two points is 119.4 m

Explanation:

1)

The motion of the object is a free fall motion, so it is a uniformly accelerated motion with constant acceleration a=g=-9.8 m/s^2 towards the ground. So, we can solve the problem by using the following suvat equation:

v=u+at

where

v is the final velocity

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In this problem we have

u = 54 m/s is the initial velocity (at point A)

v = 24 m/s is the final velocity (at point B)

a=-9.8 m/s^2 is the acceleration (negative since it is downward)

Solving for t,

t=\frac{v-u}{a}=\frac{24-54}{-9.8}=3.06 s

2)

For this part of the problem, we can use another suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

In this problem we have

u = 54 m/s

v = 24 m/s

a=-9.8 m/s^2

Solving for s, we find the distance between point A and point B, which is the distance covered by the object:

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Learn more about accelerated motion:

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Ice shoves has been recorded in at least three lakes in the past years. They are Lake Dauphin (Manitoba, Canada), Mille Lacs Lake (Minnesota), Lake Winnebago (Wisconsin), etc.

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