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3 years ago

HURRY ! the BEST I will give the brainliest

Physics

1 answer:

Oksanka [162]3 years ago

7 0

~Hello There!~

$v^{2} =u^{2} +2as$

$a = \frac{v-u}{t}$

$40^{2} =2(\frac{40-0}{8})s$

$1600 = 10s$

$s = 160$

s = distance traveled til car stopped.

180 - 160 = 20

The distance of stopped car from obstacle is 20m

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In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between

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The separation between the slits is d = 8.96

What is fringe width?

Fringe width is the distance between two consecutive bright spots (maximas, where constructive interference take place)
Or two consecutive dark spots (minimas, where destructive interference take place).

Fringe width is given by β = λL/d

In the first case fringe width is β1 = λLA /d = 625 x 10-9 x 0.36 / ( 1.4 x 10-5 ) = 0.016071428 m

The total width of the screen is 0.2 m . So, on one side of the central maximum, the width is 0.1 m

No. of fringes in this 0.1m = 0.1 / 0.016071428 = 6.222

So, since there is a bright fringe after every fringe width, the number of bright fringes on one side of central maximum is 6.

In the second case fringe width is β1 = λLAB /d = 625 x 10-9 x 0.25 / ( 1.4 x 10-5 ) = 0.011160714 m

The total width of the screen is 0.2 m . So, on one side of the central maximum, the width is 0.1 m

No. of fringes in this 0.1m = 0.1 / 0.011160714 = 8.96

So, since there is a bright fringe after every fringe width, the number of bright fringes on one side of central maximum is 8. The ninth one will not be seen since the screen is less a little less in width.

Learn more about fringe width

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<u>The complete question is -</u>

In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between the slits is d = 1.4 × 10-3 m. The total width of the screen is 0.20 m. In one version of the setup, the separation between the double slit and the screen is LA = 0.36 m, whereas in another version it is LB = 0.25 m. On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting. --Tm = 3 (Bright fringe) ++m = 0 (Bright fringe) -m = 3 (Bright fringe) Figure 27.7

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3 years ago

When dealing with the conservation of momentum, does direction matter?

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Momentum is conserved in all three physical directions at the same time.

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There is a peculiarity, however, in that momentum is a vector, involving both the direction and the magnitude of motion, so that the momenta of objects going in opposite directions can cancel to yield an overall sum of zero.

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A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.2

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To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.

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Sandra moves 14 m in 2 minutes. What is Sandra's average velocity (in m/s)?

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I would say B , not sure if its correct

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4 years ago

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HURRY ! the BEST I will give the brainliest​

HURRY ! the BEST I will give the brainliest