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3 years ago

7

Which relation is a function with range of {-1, 0, 1, 4}?

1 answer:

Jet001 [13]3 years ago

7 0

Answer:

not a function because the 1 repeats if the same x repeats it is now a function

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An online music club sells songs for $.95each plus a $1.95monthly fee for the service. If Maria’s total monthly bill was $14.30,

aksik [14]

First you would subtract the monthly fee from the total bill
$14.30 - 1.95 = 12.35$
Maria spend $12.35 on songs, to find out how many songs, you divide that by $.95
$12.35 \div .95 = 13$
Maria bought 13 songs this month.

5 0

3 years ago

4,0000000000×10,00000000

Mademuasel [1]

Answer:

yes 40

Step-by-step explanation:

she got it correct

4 0

2 years ago

Help!!!How does the slope of g(x) compare to the slope of f(x)?

attashe74 [19]

we know that

The formula to calculate the slope m between two points is equal to

$m=\frac{(y2-y1)}{(x2-x1)}$

Step $1$

<u>Find the slope of the function f(x)</u>

Let

$A( 0,-2)\\B(1,0)$

substitute the values in the formula above

$m=\frac{(0+2)}{(1-0)}$

$m=2$

<u>the slope of the function f(x) is $m=2$ </u>

Step $2$

<u>Find the slope of the function g(x)</u>

Let

$C( -4,0)\\D(0,2)$

substitute the values in the formula above

$m=\frac{(2-0)}{(0+4)}$

$m=\frac{2}{4}$

$m=\frac{1}{2}$

the slope of the function g(x) is $m=\frac{1}{2}$

therefore

slope f(x) > slope g(x)

or

slope g(x) < slope f(x)

<u>the answer is the option </u>

B.The slope of g(x) is less than the slope of f(x).

4 0

2 years ago

Read 2 more answers

Use the method of reduction of order to find a second solution to t^2y' + 3ty' – 3y = 0, t> 0 Given yı(t) = t y2(t) = Preview

Anestetic [448]

Let $y_2(t)=tv(t)$ . Then

${y_2}'=tv'+v$

${y_2}''=tv''+2v'$

and substituting these into the ODE gives

$t^2(tv''+2v')+3t(tv'+v)-3tv=0$

$t^3v''+5t^2v'=0$

$tv''+5v'=0$

Let $u(t)=v'(t)$ , so that $u'(t)=v''(t)$ . Then the ODE is linear in $u$ , with

$tu'+5u=0$

Multiply both sides by $t^4$ , so that the left side can be condensed as the derivative of a product:

$t^5u'+5t^4u=(t^5u)'=0$

Integrating both sides and solving for $u(t)$ gives

$t^5u=C\implies u=Ct^{-5}$

Integrate again to solve for $v(t)$ :

$v=C_1t^{-6}+C_2$

and finally, solve for $y_2(t)$ by multiplying both sides by $t$ :

$tv=y_2=C_1t^{-5}+C_2t$

$y_1(t)=t$ already accounts for the $t$ term in this solution, so the other independent solution is $y_2(t)=t^{-5}$ .

6 0

3 years ago

How much do 10 pieces of candy cost if 1000 pieces cost $90<br> ?<br> 10 pieces of candy cost

Masteriza [31]

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the cost per candy:

90/1000 = 0.09

Multiply this by the number of candy pieces you need:

0.09 x 10 = 0.9

They would cost $0.90

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0

3 years ago

Read 2 more answers