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Answer with explanation:</h2><h2>
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a. Given : Sample size : n= 1078
The number of adults said it was a good thing= 659
Then , the proportion of success : 
b. The conditions to determine whether you can apply the CLT to find a confidence interval are :-
- The data must be randomly sampled.
- The sample size must be large (n>30).
- The sample values should be independent of each other.
Since the given data satisfies all the above conditions , so we can apply the CLT to find a confidence interval.
c. Given : Significance level : 
Critical value : 
The confidence interval for population proportion is given by :-

Hence, a 95% confidence interval for the proportion who believe immigration is a good thing is (0.582, 0.64).