Answer: a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Explanation:
Acceleration is the rate of change in the velocity per time
a = change in velocity/time
a = ∆v/t
average acceleration a = (v2 -v1)/t. ....1
Given;
Final velocity v2 = 1.63m/s
Initial velocity v1 = -1.15ms
time taken t = 2.11s
Substituting into eqn 1
a = [1.63 - (-1.15)]/2.11
a = (1.63+1.15)/2.11
a = 2.78/2.11
a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Answer:
The object with a higher mass has three times the kinetic energy of the less massive object.
We know that K.E.= 1/2 mv²
mass of first object = 1kg
speed = v
So K.E. = 1/2mv²
= 1/2 × (1) × v²
=
Now the mass of second body = 3kg
speed = v
So K.E. = 1(3)v²/2
=
now
K.E of first / KE of 2nd
As we know that electric field at any point caused due to a point charge given by, kQ/r^2
Where, k is dielectric constant of medium, Q is the point charge and r is the distance between the point charge and point where electric field is to be measured.
Let us assume a charge of q is placed at x=+20cm to make electric field at
x=+10cm zero.
Total electric field at x=+10cm can be shown by equation,
(k X 2.20 X 10^-12)/(10-0)^2 + (k X -4.80 X 10^-12)/(10-(-11))^2 + (k X
q)/(10-20)^2 = 0
=> 2.20 X 10^-14 - 1.09 X 10^-14 + q X 10^-2 = 0
=> q = 1.09 X 10^-12 - 2.20 X 10^-12
=> q = -1.1 X 10^-12 Coulombs or -1.1 pC
Answer: Nucleosynthesis
Reason: the definition for this is “the is the process that creates new atomic nuclei from pre- existing nucleons”
Hope this helps