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malfutka [58]
3 years ago
12

Two point charges lie on the x axis. A charge of + 2.20 pC is at the origin, and a charge of − 4.80 pC is at x=−11.0cm. What thi

rd charge should be placed at x=+20cm so that the total electric field at x=+10.0cm is zero?
Physics
2 answers:
k0ka [10]3 years ago
4 0
As we know that electric field at any point caused due to a point charge given by, kQ/r^2

Where, k is dielectric constant of medium, Q is the point charge and r is the distance between the point charge and point where electric field is to be measured.

Let us assume a charge of q is placed at x=+20cm to make electric field at
x=+10cm zero.

Total electric field at x=+10cm can be shown by equation,

(k X 2.20 X 10^-12)/(10-0)^2  +  (k X -4.80 X 10^-12)/(10-(-11))^2  + (k X
q)/(10-20)^2  = 0

=> 2.20 X 10^-14 - 1.09 X 10^-14 + q X 10^-2 = 0

=> q = 1.09 X 10^-12 - 2.20 X 10^-12

=> q = -1.1 X 10^-12 Coulombs or -1.1 pC
My name is Ann [436]3 years ago
4 0

Answer: The charge must be -1.11pC

Explanation: The field done by a charge is equal to:

E(x) = k*q/(x - x')^2

Where k is the constant, q is the charge and x' is the position of the charge, then, the total field at the point x = 10cm must be also zero, we have:

E(10cm) = k*(2.20pC/(10cm - 0cm)^2 - 4.80pC/(10cm + 11cm)^2 + Q/(10cm - 20cm)^2) = 0

And we must find the value of Q.

(2.20pC/(10cm)^2 - 4.80pC/(21cm)^2 + Q/(-10cm)^2) = 0

Q = (-2.20pC/(10cm)^2 + 4.80pC/(21cm)^2)*(10cm)^2 = -1.11pC

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A 1000 kg truck moving at 2.0 m/s runs into a concrete wall. It takes 0.5 s for the truck to completely stop. What is the magnit
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Answer:

Momentum is given by

p

=

m

v

. Impulse is the change of momentum,

I

=

Δ

p

and is also equal to force times time:

I

=

F

t

. Rearranging,

F

=

I

t

=

Δ

p

t

=

0

−

20

,

000

5

=

−

4000

N

.

Explanation:

Momentum before the collision is

p

=

m

v

=

2000

⋅

10

=

20

,

000

k

g

m

s

−

1

.

Assuming the truck comes to a complete halt, the momentum after the collision is

0

k

g

m

s

−

1

.

The change in momentum,

Δ

p

, is initial minus final

→

0

−

20

,

000

=

−

20

,

000

This is called the impulse:

I

=

Δ

p

. Impulse is also equal (check the units) to force times time:

I

=

F

t

.

We can rearrange this expression to make

F

the subject:

F

=

I

t

=

Δ

p

t

=

−

20

,

000

5

=

−

4000

N

The negative sign just means the force acting is in the opposite direction to the initial momentum.

(This will be the average force acting during the collision: collisions are chaotic so the force is unlikely to be constant.)

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