Answer:
<u> Power = 9.75 ×10^8
</u>
Explanation:
- Power is rate of change of energy.
- Here gravitational energy is transferred to kinetic energy of water at a definite rate.
For one second 650m^3 of water flows out down to 150m oh depth.
So, the energy at a height of 150m is transformed to kinetic energy.
for a second,
650m^3 of water flows down ⇒ (1000kg/m^3 × 650m^3) = 6.5×10^5kg of warer flos down.
The total gravitational potential energy stored in water is
= <u>mass of water × height× gravity</u>
= 6.5 ×10^5 × 150 × 10 = 9.75 ×10^8
As it is transformed in a second it is also equal to <u>Power.</u>
This problem is looking for the minimum value of μs that is
necessary to achieve the record time. To solve this problem:
Assuming the front wheels are off the ground for the entire
¼ mile = 402.3 m, the acceleration a = µs·9.8 m/s².
For a constant acceleration, distance = 402.3
m = 1/2at^2 = 804.6 m / (4.43 s)^2 = a = µs·9.8 m/s^2
µs = 804.6 m / (4.43s)^2 / 9.8 m/s^2 = 4.18
Answer:
Explanation:
We need to find the energy for an electron to jump from n = 1 to n = 4.
The energy in transition from 1 state to another is given by :
The difference in energy for n = 1 to n = 4 is:
So, the required energy is equal to 
.
Answer:
A derived quantities is terms of the 7 base quantities via a system of quantity equations which are called SI derived units.
Explanation: there you go:)
Acceleration=9.81m/s^2
initial velocity=0m/s
time=.28s
We have to find final velocity.
The equation we use is
Final velocity=initial velocity+acceleration x time
Vf=0m/s+(9.81m/s^2)(.28s)
Vf=2.7468m/s
We would round this to:
Vf (final velocity)=2.7m/s
