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Nataliya [291]
2 years ago
11

A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...

Physics
1 answer:
allochka39001 [22]2 years ago
7 0

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

f=\frac{v}{\lambda} where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

75=\frac{347}{\lambda} and

\lambda=\frac{347}{75} so

\lambda=4.6m

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Consider an electric dipole in a uniform electric field. In which orientation does the dipole-field system have the greatest pot
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Explanation: The formulae that relates the potential energy of a dipole, dipole moment and strength of electric field is given as

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Where, u= dipole potential energy, p = dipole moment, E = strength of electric field.

The expression is at maximum when θ = 0 (cos 0° = 1)

Hence the function for potential energy will be greatest when θ = 0° which implies that the dipole moment and strength of electric field are parallel to each other.

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Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a
babymother [125]

Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

Weight is 8500 N

And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force

8 0
2 years ago
Please help me with this question :
aalyn [17]

Answer:

  • 514.27 ( wavelength )

the color is green

  • 602.93 nm  ( orange color )

the observation is that there is a change of visible color

Explanation:

A) wavelength of visible light that is most strongly reflected from a point on a soap

refraction n = 1.33

wall thickness (t) = 290 nm

2nt = (2m +1 ) ∝/2 -----equation 1

note when m = 0

therefore ∝ =  4nt/ 1 = 4 * 1.33 * 290 = 1542.8nm we will discard this

when m = 1

equation 1 becomes

∝ = 4nt/3 =( 4 * 1.33 * 290) /  3 = 1542.8 / 3 = 514.27 ( wavelength )

the color is green

B) the wavelength when the wall thickness is 340 nm

∝ = 4nt / 2m +1

where m = 1

∝ = (4 * 1.33 * 340 ) / 3  = 1808.8 / 3 = 602.93 nm  ( orange color )

the observation is that there is a change of visible color

7 0
3 years ago
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