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kotykmax [81]
4 years ago
9

if vector v has an initial point at (2,3) and a terminal point at (6,6) and vector w has an initial point at (3,2) and a termina

l point at (6,6), are the two vectors equivalent?​
Mathematics
1 answer:
Elanso [62]4 years ago
5 0
<h2>Not equivalent</h2>

Step-by-step explanation:

For any two vectors v_{1} and v_{2} to be equivalent,

their length and direction has the same.

Distance between two points (x_{1},y_{1}) and (x_{2},y_{2})

is \sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^{2}}

Length of v_{1} is \sqrt{(6-3)^{2}+(6-2)^{2}}=\sqrt{9+16}=\sqrt{25}=5

Length of v_{2} is \sqrt{(6-2)^{2}+(6-3)^{2}}=\sqrt{16+9}=\sqrt{25}=5

Slope of vector v joining (x_{1},y_{1}) and (x_{2},y_{2}) is \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

slope of v_{1} = \frac{6-3}{6-2} =\frac{3}{4}

slope of v_{2} = \frac{6-2}{6-3} =\frac{4}{3}

since slope of v_{1} is not equal to slope of v_{2},the vectors are not equivalent.

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Can someone help me with this? Thanks!
Evgesh-ka [11]

Part (a)

There are 3 face cards (jack, queen, king) in any given suit. We have 4 suits. That gives 3*4 = 12 face cards total.

12/52 = 3/13 is the probability of getting a face card on any random selection. This probably does <u>not</u> change for any future selection because we put the current card back. In other words, the deck has not changed. Contrast this with part (b) where the probabilities will change since the card counts decrease each time (since we don't put the card back).

The probability of getting 3 face cards in a row, with replacement, is:

(3/13)*(3/13)*(3/13) = 0.012289 approximately

This converts to the percentage 1.2289% after moving the decimal point two spots to the right. This is the same as multiplying by 100.

Lastly, round that to one decimal place to get 1.2%

<h3>Answer:  1.2</h3>

The percent sign is already taken care of, so you'll just input the number only.

=============================================================

Part (b)

Like mentioned earlier, the probability of a face card is 12/52

I won't reduce that fraction, as you'll see why below.

After that first card is <u>not</u> put back, the 12 decreases to 12-1 = 11 and we have 52-1 = 51 cards left over.

11/51 is the probability of getting another face card, where we have no replacement going on.

Then 10/50 is the probability of getting a third face card. Again, with no replacement.

Therefore,

(12/52)*(11/51)*(10/50) = 0.009955

is the approximate probability of getting 3 face cards in a row with no replacement. Notice the count down 12,11,10 in the numerators. There's also the countdown 52, 51, 50 in the denominators. This nice pattern only happens if we don't reduce the reducible fractions. This is why I didn't reduce.

Anyways 0.009955 converts to 0.9955% which rounds to 1.0% or simply 1%

<h3>Answer:   1</h3>
4 0
3 years ago
!HELP! SHOW WORK PLEASE SO I CAN UDNERSTAND!
Nata [24]
Ok.

The volume of a cone is the volume of a cylinder over 3.

The volume of a cone is:
\frac{1}{3} \pi r^{2}h

This problem gives us the diameter, which is twice of the radius.  So, we'll just half it.
Radius (me) = 4 cm.

Substitute our given values into the equation.
\frac{1}{3} \pi (4)^{2}h \ or \  \frac{1}{3} \pi (4)^{2}(10) \ or \  \frac{1}{3} \pi (16)(10)

Multiply
\frac{1}{3} \pi(160) \ or \  \frac{1}{3} (3.14)(160) \ or \ 1.047(160)

Multiply
167.52 \ cm^{3}

This would make 167 \ cm^{3} the closest option.
4 0
4 years ago
Read 2 more answers
Helpppppp plzzz10points
navik [9.2K]

y=47.38+.617x

130 = 47.38+.617x

subtract 47.38 from each side

82.62=.617x

divide by .617 on each side

133.906 =x

to the nearest minute x=134

Answer Choice C

3 0
4 years ago
Please help me with all these questions . I really appreciate it but if you don't how to do it please comment don't answer the q
frozen [14]
For number 1, add the sides of the triangle. They are all given. The answer is 19.

For number 2, you use the formula for circumference, 2 times pi times radius. The answer is 43.96.

For number 3, I assume that 5 is half of one side. You would double 5 to get ten and multiply it by four, since there are four sides in a square. The answer is 40.

For number 4, you would multiply 5 times pi, but don't solve it. ( since the directions are to leave the answer in terms of pi) The answer is 5 pi.

For number 5, add all the sides together like number 1. The answer is 18.
8 0
3 years ago
Read 2 more answers
Please help!
qwelly [4]
It could be -1, 1, and 2
5 0
3 years ago
Read 2 more answers
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