Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
The statistical question would be B.
For example, Pi, which is 3.14159265359...
Answer:
I believe the correct answer would be A.) Profit.
Step-by-step explanation:
This is because <em>revenue</em> is the amount earned, which, in this case is $100,000. Loss is not a proper term. The proper term would be <em>expense. </em>This is the amount spent or lost. The correct answer would be <em>profit. </em>Profit just means the amount left after the expenses have been deducted from the revenue.
Hope this helps,
♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥
The equation of a circle is (x - h)^2 + (y - k)^2 = r^2
x and y are left alone in a circle equation, while h and k are the coordinates of the center.
Thus, our equation is (x - 7)^2 + (y + 2)^2 = 61