The volume will be one third of the original volume of an ideal gas.
Boyle’s law depicts the relationship between the pressure ,volume and the temperature of a gas. Boyle’s law states that the pressure of a gas is inversely proportional to its volume at a constant temperature.
P ∝ 1 / V
Or, PV = k
When the temperature is kept constant.
According to the question, when the pressure is increased from 2 atm to 6 atm , the pressure is increases thrice ,hence the volume will decrease three times simultaneously of the original volume of 1 mol of an ideal gas.
The equation of the Boyle’s law is; P1V1 = P2V2
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Electric current is necessary to transmit , encode and analyse information
(a) 33.6 L of oxygen would be produced.
(b) 106 grams of 
would be needed
<h3>Stoichiometric calculations</h3>
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of 
produce 3 moles of 
. 1 mole of will, therefore, produce 1.5 moles of .
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of 
is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of requires 1 mole of .
Molar mass of = (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole = 1 x 106 = 106 grams
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