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(a) 33.6 L of oxygen would be produced.
(b) 106 grams of would be needed
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of produce 3 moles of
. 1 mole of
will, therefore, produce 1.5 moles of
.
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of requires 1 mole of
.
Molar mass of = (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole = 1 x 106 = 106 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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The expression that can be used to determine Cl2O(g) is ;
The general expression for ΔS°rxn of a chemical reaction
ΔS°rxn = ∑mS°products - ∑nS°reactants
where ; m and n = stoichiometry coefficients
Considering the given reaction : H₂O(g) + Cl₂O(g) → 2HCIO (g)
S°rxn =
------- ( 2 )
Rearranging the equation above
Hence we can conclude that The expression that can be used to determine Cl2O(g) is ;
Learn more about stoichiometry : brainly.com/question/16060223