Question

Need help please?!!!!!​

Answer 1

(a) 33.6 L of oxygen would be produced.

(b) 106 grams of  $Na_2CO_3$ would be needed

Stoichiometric calculations

1 mole of gas = 22.4 L

(a) From the equation, 2 moles of $KClO_3$ produce 3 moles of $O_2$. 1 mole of  $KClO_3$ will, therefore, produce 1.5 moles of  $O_2$.

1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L

(b) 22.4 L of $CO_2$ is produced at STP. This means that 1 mole of the gas is produced.

From the equation, 1 mole of  $CO_2$ requires 1 mole of $Na_2CO_3$.

Molar mass of  $Na_2CO_3$ = (23x2)+ (12)+(16x3) = 106 g/mol

Mass of 1 mole  $Na_2CO_3$ = 1 x 106 = 106 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1