If you want 1,775 mL of 48 M MgCl2 solution, how many grams of MgCl2 do you need?

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][I^-]$

$1\times 10^{-12}=0.0079\times [I^-]$

$[I^-]=1.25\times 10^{-10}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgI\rightleftharpoons Ag^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][I^-]$

$8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M$

$[Ag^+]=6.64\times 10^{-7}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{6.64\times 10^{-7}}{0.0087}\times 100$

Percent of $Ag^+$ remains = 0.0076 %

8 0

4 years ago

Equations can be balanced by using the half-reaction method. Which step should be completed immediately after finding the oxidat

Dovator [93]

After finding the oxidation states of atoms, you identify the half reactions (option c).

The half reactions are given by the change of the oxidation states of the atoms.

For example if Cu is in the left side with oxidation state 0 and in the other side with oxidation state 2+, then there you have a half reaction (oxidation reaction). And if you have O with oxidation state 0 in the left side and with oxidation state 2- in the right side, there you have other half reaction (reducing reaction).

8 0

4 years ago

Read 2 more answers

What fraction of a sample of ³H will be left after 36.78 years while undergoing beta decay with a half-life of 12.26 years?

frutty [35]

Explanation:

no lo c crack solo es para poder iniciar la sección y no c ingel Jaksjs

7 0

3 years ago

What is the IUPAC name for this product?

mihalych1998 [28]

The IUPAC name for the given product is 2 chloro Butane.

<h3>What is IUPAC nomenclature?</h3>

IUPAC stands for 'International Union of Pure and Applied Chemistry', which givers some rule for designing the name of compounds of chemistry.

In the given product total four carbon atoms are present and between all of them single bonds are present.
In the second carbon atom, chlorine group is present.
During the nomenclature process, first we write down the name of the attached group which is followed by the alkane chain.

Hence name of the product is 2 chloro Butane.

To know more about IUPAC nomenclature, visit the below link:

brainly.com/question/26635784

#SP1

7 0

2 years ago

What are the respective hybridizations of the imine nitrogen and carbonyl carbon of the CPV B-state as it is depicted in the pas

horsena [70]

Answer:

C) sp2 and sp2

Explanation:

The hybridization depens on the ammount and type of bonds the atom analized has in the molecule.

For example:

A C atom bonded to 4 H atoms has a sp3 hybridization.
A C atom bonded to 2 H atoms and to 1 C with a double bond (like in ethene) has a sp2 hybridization
A C bonded to 1 H and 1 C with a triple bond (like in ethyne) has a sp hybridization.

Analyzing the type and amount of unions of the nitrogen and the carbonyl you will be able to determine the hybridization.

In the imine, the N atom has a double bond to a C and a simple bond two other C, plus the lone pair of electrons (counts as a bond) so it will have a sp2 hybridization.

In the carbonyl, the C has two simple bonds to other C and a double bond to an oxygen atom. It will also have a sp2 hybridization

3 0

3 years ago