9: I think it is 48
10: 138
Answer:
what happened
Step-by-step explanation:
Question
During one waiters shift he delivered 13 appetizers, 17 entrées, and 10 desserts what percentage of the dishes he delivered were: A. Desserts B. Appetizers C. entrees
Answer:
A)Desserts = 25 %
B)Appetizers = 32.5 %
C)Entrées = 32.5 %
Step-by-step explanation:
<u>Given:</u>
Number of appetisers = 13
Number of entrees = 17
Number of desserts = 10
<em><u>A. percentage of the dishes he delivered were Desserts</u></em>
Percentage of Desserts = 
Total number of dishes = 13 + 17 + 10 = 40
Percentage of Desserts = 
Percentage of Desserts = 
Percentage of Desserts = 25 %
<em><u>B. percentage of the dishes he delivered were Appetizers </u></em>
Percentage of Desserts = 
Percentage of Desserts = 
Percentage of Desserts = 
Percentage of Desserts = 32.5 %
<em><u>C. percentage of the dishes he delivered were Entrées </u></em>
Percentage of Desserts = 
Percentage of Desserts = 
Percentage of Desserts = 
Percentage of Desserts = 42.5 %
Number: n
square of number: n^2
sum of n and n^2 is n+n^2=20
Rewriting this equation, we get n^2+n-20=0 = (n+5)(n-4) = 0
Then n+5=0 and n-4=0, so n = -5 and n = 4.
You must check both results. It could happen that both are correct, or that only one is correct.

recall that, log <--- with no apparent base, implies base10, so you can just plug that in your calculator
for the change of base rule, it doesn't really matter what base you use, so long is the same above and below, it just so happen, that we used base10 in this case, but could have been anything, same result.