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Ulleksa [173]
2 years ago
11

PLZ HELP!!!!!!!!!!!!!! WILL MARK BBRAINLIST

Mathematics
1 answer:
balandron [24]2 years ago
4 0

Answer:

B. The second choice.

Step-by-step explanation:

A function cannot have two points with the same x-coordinate.

If you graph two different points that have the same x-coordinate, they will both lie on the same vertical line. Therefore, if in a relation, more than one point lie on the same vertical line, then the relation is not a function.

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A city manager made a scatter plot of the number or retail store in a certain city over the years. the scatter plot had a trend
Fiesta28 [93]

Answer:

155

Step-by-step explanation:

The problem sounds complicated, but it's not. Let's analyse.

The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.

We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.

Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).

In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.

y= 11x + 12

=> In Tracy's case: y= 11*13 + 12= 155

So the number of retail stores there were in 2003 was 155

5 0
2 years ago
Ashley earns $5 per hour babysitting. How much will she earn in 3 hours?
fgiga [73]

Ashley will get $15 because it like 3X5=15

7 0
3 years ago
Round 1964.15569 to the nearest​ hundredth, tenth,​ one, ten, and hundred.
Umnica [9.8K]
1964.16 is hundredth
1964.2 is tenth
1964 is one
1960 is ten 
2000 is hundred
6 0
3 years ago
PLEASE HELP ILL GIVE 5 star
dezoksy [38]

Answer:

it is D hope this helps

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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