The answer is B.55.8. Hope this helps!!
2t+3n=9 2(2)+3n=9
+5t-3n=5 (the 3n cancel out) 4+3n=9
7t=14 3n=5
t=2 n=5/3 or 1.67
Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
Step-by-step explanation:
Try and become familiar with a program like Desmos. It will do wonderful things for you.
I have graphed
Red: y = -2x + 5 (The 5 is the y intercept. For this question it could be anything.
Blue: y = - 4x + 5 Same note as above.
Answer:100 times 7
Step-by-step explanation: because
