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slava [35]
3 years ago
15

Instantiate an array, load it with values, total up all of the values in the array. finally, find the average of all of the valu

es.
Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0
It seem like there are information missing on the question posted. Let me answer this question with all I know. So here is what I believe the answer is,  <span>Instantiate an array, load it with values, total up all of the values in the array. finally, find the average of all of the values.</span>

Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
You might be interested in
V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

7 0
3 years ago
Plz Help me<br><br>3x + 5y = 13 <br>2x + y = 4​
Finger [1]

Answer:

solve simultaneously

start by labeling them equation 1 and 2 then choose whether you want to make x or y the subject from knew of the equations

7 0
3 years ago
Cube A and cube B are similar solids. The volume of cube A is 27 cubic inches, and the volume of cube B is 125 cubic inches. How
katovenus [111]

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

<h3>How many times larger is the base area of cube B than the base area of cube A? </h3>

Because the cubes are similar, then we know that the dimensions of cube B are a dilation of scale factor K of the dimensions of cube A.

Then, the volume of cube B is K³ times the volume of cube A.

The area of any face of cube B is K² times the area of any face of cube A

From this we can write:

125 in³ = K³*27in³

(125/27) = K³

If we apply the cubic root in both sides, we get:

∛(125/27) = K = 5/3

Then the relation between the areas is equal to:

K² = (5/3)^2 = 25/9

The area of the base of cube B is 25/9 times larger than the area of the base of cube A.

If you want to learn more about dilations:

brainly.com/question/3457976

#SPJ1

5 0
2 years ago
Please help meeeeeeeee help help please
I am Lyosha [343]

Answer:

27. My fiend solved the inequality correctly but graphed it incorrectly. The statement "x > 5" is correct but but since the symbol is "greater than" it should have been graphed with an open circle to the right rather than a closed circle to the right.

28. My friend is incorrect for both solving the inequality and graphing. The correct answer for solving the inequality would be "5 ≥ x ". And for graphing the correct answer would be closed circle to the right since the symbol is greater than.

Step-by-step explanation:

27. Solving the inequality

x - 7 > -2

+ 7 + 7

------- ------

0 5

answer: x > 5

Graphing the inequality

Since the symbol is greater than, it would be a open circle to the right because the the right of the number line is positives and the bigger numbers. It would be an open circle because unlike question 28 the symbol is just greater than, not greater than or equal to.

28. Solving the inequality

8 ≥ x + 3

-3 - 3

-------- --------

5 0

answer: 5 ≥ x

Graphing the inequality

Since the symbol is greater than than or equal to, it would be a closed circle to the right because the the right of the number line is positives and the bigger numbers. It would be an open circle because unlike question 27 the symbol is just greater than or equal to, not just greater than.

This might not be the right way to do it or the right answer for that matter, I am very new to solving and graphing inequalities so I just decided to give this one a shot.

Hope this helps ; )

7 0
3 years ago
In 1839, Georgia produced 326,000 bales of cotton . By 1860, the state produced 700,000 bales. What was the approximate percent
hammer [34]

Answer: 115% increase

Step-by-step explanation: To solve, we need to subtract the first value fro the second value. The formula is Percent Change = ((Second Value – First Value) ÷ First Value) x 100%

700,000-326,000=374,000. Then, divide the difference by the first value.

374,000÷326,000=1.1472392638≈1.15

1.15×100%=115%

Thus, the approximate percent of increase in the bales produced during that 21-year period is 115% increase

3 0
3 years ago
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