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slava [35]
3 years ago
15

Instantiate an array, load it with values, total up all of the values in the array. finally, find the average of all of the valu

es.
Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0
It seem like there are information missing on the question posted. Let me answer this question with all I know. So here is what I believe the answer is,  <span>Instantiate an array, load it with values, total up all of the values in the array. finally, find the average of all of the values.</span>

Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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What does x equal 7(2x+5)=4x -9 -x <br> PLEASEEEE HELPPPP ME
Gennadij [26K]

Answer: x=-4

Step-by-step explanation:

Given

7(2x+5)=4x-9-x

Expand parenthesis

14x+35=4x-9-x

Combine like terms

14x+35=3x-9

Subtract 35 on both sides

14x+35-35=3x-9-35

14x=3x-44

Subtract 3x on both sides

14x-3x=3x-44-3x

11x=-44

Divide 11 on both sides

11x/11=-44/11

x=-4

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
Suppose we have three urns, namely, A B and C. A has 3 black balls and 7 white balls. B has 7 black balls and 13 white balls. C
professor190 [17]

Answer:

a. 11/25

b. 11/25

Step-by-step explanation:

We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

Then , P(A1 + P(A2) +P(A3) =1 ....(1)

And P(A1):P(A2):P(A3) = 1: 2: 2 (given) ....(2)

Let P(A1) = x, then using equation (2)

P(A2) = 2x and P(A3) = 2x

(from the ratio given in the question)

Substituting these values in equation (1), we get

x+ 2x + 2x =1

Or 5x =1

Or x =1/5

So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

=11/25

(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

​​

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It's the first choice.Correlation that implies causation
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