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Salsk061 [2.6K]
3 years ago
13

According to the Quantum Atomic Theory of an atom, in an orbital

Chemistry
1 answer:
amm18123 years ago
4 0

Answer:

1) B

2) D

3) D

Explanation:

Quantum atomic theory was introduced in order to explain the behavior of subatomic particles, which could not be explained using classical physics and dynamics. Many scientists contributed to this, one of them being Heisenberg, who introduced the principle of uncertainty, stating that we can not determine the exact location and direction of motion of electron, and that there are regions of an atom in which the electrons most likely reside. These regions are called the orbitals.

Each atom consists of several energy levels (shells), depending on the number of electrons it has. They are distributed in these levels around the nucleus. Further, these levels are from the nucleus, higher the energy level is. Each shell consists of subshells, which consist of several orbitals, Each orbital has two electrons. So:

-s subshell has 1 orbital, or 1 • 2 = 2 electrons

-p subshell has 3 orbitals, or 3 • 2 = 6 electrons

-d subshell has 5 orbitals, or 5 • 2 = 10 electrons

-f subshell has 7 orbitals, or 7 • 2 = 14 electrons

etc.

When writing abbreviated or condensed electronic configuration we look up to the previous noble gas. This is used to avoid confusion and errors when writing configuration for atoms with a lot of energy levels and orbitals. We use noble gases because they are stable, inert or unreactive because their energy levels are completely filled, so we can use them as a basis on which we add excess electrons from the given atom.

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if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d
Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g

We can calculate the mass percent of O in MgO using the following expression.

\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\%  = 40.0 \%

You can learn more about mass percent here: brainly.com/question/14990953

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Which atom attracts electrons more strongly?
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Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
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Answer:please can you help me with the last question that I asked I will help you if you help me please help

Explanation:

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