Answer:
ICE Table Figure
a. 67.37 g 
b. 35.62 g 
c. 58.61 g
Explanation:
For the <u>ICE table </u>we have to keep in mind that we have 4 moles of
and 1 mol of
and the reactives are consumed, so for
we will have -4X and for
we will have -X. Follow the same logic we will have -4X for
.
a. <u>Mass of the product</u>
Molar mass of
= 256.52 g/mol
Molar mass of
=70.9 g/mol
Molar mass of
=135.03 g/mol
We have to find the limiting reagent in the reaction:



Divide by the coefficients in the balanced reaction:


The limiting reagent would be 
Now is posible to calculate the amount of
produced:

b. <u>Mass in excess</u>


C. <u>87%Yield</u>

Oxygen
I think
Hope this helps
Answer:
M = 1.18 mol/L
Explanation:
Moles is denoted by given mass divided by the molecular mass ,
Hence ,

n = moles ,
w = given mass ,
m = molecular mass .
From the information of the question ,
w = 78.3 g
As we known ,
molecular mass of
is 189.36 g/mol
m = 189.36 g/mol
moles can be calculated as -

n = 0.413 mol
MOLARITY -
Molarity of a substance , is the number of moles present in a liter of solution .

M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
From the question ,.
V = 350 mL
Since , 1 mL = 10⁻³ L
V = 0.350 L
n = 0.413 mol
Molarity can be calculated as -

M = 1.18 mol/L
Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).
Hope this helps :)