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Art [367]
3 years ago
12

The 2 in the formula AgS is a1. coeffcient2. subscript3. superscript4. binomial​

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

Subscript, or B

Explanation:

<em>AgS is the equation for the chemic reaction of Silver + Sulfur, since the subscript of 2 goes by the g in the equation, this would equal subscript.</em>

<em />

<em>Remember subscripts are located at the BOTTOM of a coefficient and superscripts are located at the TOP of a coefficient.</em>

<em />

<em>Hope this supported your learning journey through and through! Don't forget to drop me a Brainliest! (No pressure, only if you want to!) (◠△◠✿) Sincerely, Kelsey from Brainly.</em>

<em />

<em>~ #LearnWithBrainly ~</em>

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Hey There!

Here is your answer:

The answer is a compound machine!

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A(n) _____ reaction is a reaction in which an acid and a base react in an aqueous solution to produce a salt and water.
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<span>A neutralization reaction is a reaction in which an acid and a base react in an aqueous solution to produce a salt and water. An example of a neutralization reaction is the reaction of sodium hydroxide and hydrogen chloride to form sodium chloride and water. Answer is C.</span>
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3 years ago
How is an electrons energy related to its position in an atom?
balu736 [363]

Answer: The amount of energy needed to move an electron from one zone to another is a fixed, finite amount. The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.

Explanation:

6 0
3 years ago
A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid
Len [333]

The molar mass of the acid if 28. 5 ml of the koh solution is required to neutralize the sample is 90.23g/mol.

<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

Given,

Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

Moles = (0.18× 28.5)/1000

= 0.00513 mol

<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

Given,

Mass of HA = 0.462 g

Moles of HA = 0.00512 mol

0.00512 = 0.462/ Molar mass

Molar mass = 90.23 g/ mol.

Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

#SPJ4

3 0
1 year ago
Give the n and l values and the number of orbitals for sublevel 5g.
Pepsi [2]

The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

There are total four quantum numbers:

1) Principal quantum number , n

2) Angular quantum number , l

3) Magnetic quantum number , ml

4) spin quantum number , ms

For 5g shell, n = 5

subshell g , l = 4     ....0 - s , 1 - p , 2 - d, 3 - f, 4 -g

number of orbitals in subshell = (2l + 1)  ( 2×4 + 1) = 9

Thus,  The n and l values and the number of orbitals for sublevel 5g is :

5g shell , n= 5 subshell g , l = 4, Number of orbitals for sublevel = 9.

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6 0
1 year ago
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