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3 years ago

When the weather change and temperatures get hot what do wolves use to cool down

2 answers:

7 0

When the seasons change from winter to spring, the wolves inner layer of fur, which traps air and insulates the wolf from harsh cold temperatures, is shed to keep the wolf cool when the heat starts to come back.

swat323 years ago

3 0

The wolves get an interior of fur to keep warm and to cool down

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1. Cancer is a disease in which cells

levacccp [35]

Answer:

1. a

2. a.

3. b.

4. a.

5. c.

6. b.

7. a.

8. c.

Explanation:

7 0

3 years ago

A sample of methane occupies a volume of 174.0 mL at 25 C and exerts a pressure of 1030.0 mmHg if the volume of the gas is allow

PolarNik [594]

Answer:

The pressure will be 0,37 atm.

Explanation:

We use the Boyle Mariotte´s formula,where for a given mass of gas, at constant temperature, the pressure and temperature vary inversely proportionally. We see here that the initial and final temperature does not vary (298K).

We convert the unit Celsius into Kelvin (0 ° C = 273K) and the unite mmHg into atm (760mmHg=1 atm):

25°C= 25+273=298K ; (1060mmHgx 1 atm)/760mmHg)=1,39 atm.

We convert unit of volume from ml to L: 174/1000=0,174L and 650/1000=0,650L

P1xV1= P2xV2

1,39 atm x 0,174L =P2 x0,650L

P2= (1,39 atm x 0,174L)/0,650L= 0,37 atm

4 0

4 years ago

Read 2 more answers

1. How many grams of Mg(OH)2 are there in 4.5 moles?

Ket [755]

Answer:

1) 262 grams

Explanation:

Mg = 24.305g

O = 16g

H = 1

24.305 +2(16)+2(1) = 58.305 g

× $\frac{58.305g}{1} = \frac{x }{4.5 } =262.37 g$

7 0

3 years ago

1. Consider the peptide with amino acid sequence NICE. Write the full name and the three-letter abbreviations of the amino acids

Alex Ar [27]

Answer:

I think its c i did a lil research

6 0

3 years ago

Magnesium metal reacts with iodine gas at high temperatures to form magnesium iodide. what mass of mgi2 can be produced from the

sergiy2304 [10]

<span>54.8 g of MgI2 can be produced. To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium Atomic weight of Iodine = 126.90447 Atomic weight of Magnesium = 24.305 Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394 Now determine how many moles of Iodine and Magnesium you have moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent. So figure out how many moles of magnesium will be consumed by the iodine 0.393997154 mole / 2 = 0.196998577 mole. This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2 0.196998577 mole * 278.11394 g/mole = 54.78805 g Round the result to the correct number of significant figures. 54.78805 g = 54.8 g</span>

5 0

4 years ago