<span>Magnesium????
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Within each functional group, the boiling points of members of the group vary according to molecular weight. Therefore, one cannot deduce any functional group from boiling points.
Organic compounds are divided into families called homologous series. Each homologous series has a functional group common to all the members of the series. As a result of this, the chemical properties of all the members of the homologous series are similar.
However, the boiling points of the members of a homologous series vary according the their molecular weights. As such, boiling points can not be used as evidence to classify substances into any particular homologous series.
Summarily, one cannot deduce any functional group from physical properties.
Learn more: brainly.com/question/1078956
Answer:
Ka = 0.1815
Explanation:
Chromic acid
pH = ?
Concentration = 0.078 M
Ka = ?
HCl
conc. = 0.059M
pH = -log(H+)
pH = -log(0.059) = 1.23
pH of chromic acid = 1.23
Step 1 - Set up Initial, Change, Equilibrium table;
H2CrO4 ⇄ H+ + HCrO4−
Initial - 0.078M 0 0
Change : -x +x +x
Equilibrium : 0.078-x x x
Step 2- Write Ka as Ratio of Conjugate Base to Acid
The dissociation constant Ka is [H+] [HCrO4−] / [H2CrO4].
Step 3 - Plug in Values from the Table
Ka = x * x / 0.078-x
Step 4 - Note that x is Related to pH and Calculate Ka
[H+] = 10^-pH.
Since x = [H+] and you know the pH of the solution,
you can write x = 10^-1.23.
It is now possible to find a numerical value for Ka.
Ka = (10^-1.23))^2 / (0.078 - 10^-1.23) = 0.00347 / 0.0191156
Ka = 0.1815
Sucrose is stored in dry and closed container, sealed properly.
Explanation:
- Sucrose is nothing but the table sugar which we use daily in our life.
- Sucrose is formed by the combination of fructose and glucose so, it called a disaccharide because two monosaccharides are converted to form sucrose.
- It is a hygroscopic substance. The hygroscopic substance is which is easily vulnerable to water absorption. They tend to absorb water if they are being exposed to humid places.
- Hence, it should be kept in a dry and close container, sealed properly.
Answer:
The specific heat of water is 4.18 J/g C.
Explanation:
q
=
m
C
s
Δ
T
Never forget that!
2200
=
m
⋅
4.18
J
g
⋅
°
C
⋅
66
°
C
∴
m
≈
8.0
g
