What happens to the particles in a substance as it freezes?

If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.

nekit [7.7K]

Answer:

$16.1\times 10^3\ \text{g}$

$16.1\times 10^{6}\ \text{mg}$

$16.1\times 10^{9}\ \mu\text{g}$

Explanation:

Mass of dog = $16.1\ \text{kg}$

$1\ \text{kg}=10^{3}\ \text{g}$

$1\ \text{kg}=10^{6}\ \text{mg}$

$1\ \text{kg}=10^{9}\ \mu\text{g}$

So,

$16.1\ \text{kg}=16.1\times 10^3\ \text{g}$

$16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}$

$16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}$

Mass of the dog in the other units is $16.1\times 10^3\ \text{g}$ , $16.1\times 10^{6}\ \text{mg}$ and $16.1\times 10^{9}\ \mu\text{g}$ .

3 0

2 years ago

A balloon was partially filled with helium gas at room temperature. It occupied 4.0 liters of volume at 700.0 mmHg atmospheric p

Tatiana [17]

Answer:

28.28 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have two different values of V and P:

P₁V₁ = P₂V₂

P₁ = 700.0 mm Hg, V₁ = 4.0 L.

at burst: P₂ = 99.0 mm Hg, V₂ = ??? L.

∴ V₂ = P₁V₁/P₂ = (700.0 mm Hg)(4.0 L)/(99.0 mm Hg) = 28.28 L.

3 0

3 years ago

Are spiders scared of weed?

ki77a [65]

Answer:

yes the smoke from it scares them it also if, i remeber correctly, the smoke puts them to sleep

Explanation:

4 0

2 years ago

Read 2 more answers

If you burned 4.10 x 10^24 molecules of butane (C4H10), what mass of ethane did you burn?

LenKa [72]

Answer:

Explanation:

Molar mass of C4H10 = 12x 4 + 1 x 10= 48+ 10=58g.

Also note that molar mass of a substance is equivalent to Avogadro's number (6.02 X 10^-23)

Hence,

6.02 X 10^-23 molecules of ethane was burned in 58g of ethane

So, 4.10 X 10^24 molecules of ethane will burn in xg of ethane.

Cross multiply:

6.02 X 10^-23x = 58 X 4.10 X 10^24

6.02 X 10^-23x = 2.378 X 10 ^26

Dividing both sides by the coefficient of 'x'

x = 2.378 X 10^26/(6.02X 10^-23)

x = 3.95 X10^48g approximately

x = 4.0 X 10^48g

Or

Mole = number of elementary

particless / Avogadro's number

Where,

No of elementary particles= 4.10 X 10^24 molecules

Avogadro's number= 6.02 x 10^-23

Therefore,

Mole = 4.10 X 10^24/ (6.02 X 10^-23)

= 6.81 X 10^ 46 moles.

But mole = mass / molar mass

Mass = mole x molar mass

where

Molar mass of C4H10 = 12x 4 + 1 x 10= 48+ 10=58g/mol

Mass= 6.81 X 10^46 X 58

= 3.95 X 10^48g approximately

= 4.0 X 10^ 48g.

Thanks

8 0

2 years ago

A solution of copper sulfate is treated with zincmetal. How many grams of copper are produced if 2.9 g of zinc are consumed?

Marat540 [252]

Answer:

2.8212 g

Explanation:

The reaction of copper sulfate with zinc is shown below as:

$CuSO_4+Zn\rightarrow ZnSO_4+Cu$

Given that :

Amount of zinc = 2.9 g

Molar mass of zinc = 65.38 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, molesare:

$moles= \frac{2.9\ g}{65.38\ g/mol}$

$moles= 0.0444\ mol$

From the reaction,

1 mole of zinc on reaction forms 1 mole of copper

Thus,

0.0444 moles of zinc on reaction forms 0.0444 mole of copper

Mass of copper = moles×Molar mass

Molar mass of copper = 63.54 g/mol

Mass of copper = 0.0444 ×63.54 g = 2.8212 g

7 0

3 years ago